NO
* Step 1: FromIts NO
    + Considered Problem:
        Rules:
          0. f1(A) -> f1(B) [1 >= B && 1 + B >= 0 && C >= 2] (?,1)
          1. f0(A) -> f1(B) [B >= 2]                         (1,1)
        Signature:
          {(f0,1);(f1,1)}
        Flow Graph:
          [0->{0},1->{0}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: CloseWith NO
    + Considered Problem:
        Rules:
          f1(A) -> f1(B)  [1 >= B && 1 + B >= 0 && C >= 2]
          f0(A) -> f1(B)  [B >= 2]
        Signature:
          {(f0,1);(f1,1)}
        Rule Graph:
          [0->{0},1->{0}]
    + Applied Processor:
        CloseWith False
    + Details:
        ()

NO