NO
* Step 1: FromIts NO
    + Considered Problem:
        Rules:
          0. f2(A,B,C,D) -> f0(0,B,C,D)      True                  (1,1)
          1. f0(A,B,C,D) -> f0(-1 + A,B,A,D) [-1*A >= 0 && 9 >= A] (?,1)
        Signature:
          {(f0,4);(f2,4)}
        Flow Graph:
          [0->{1},1->{1}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: CloseWith NO
    + Considered Problem:
        Rules:
          f2(A,B,C,D) -> f0(0,B,C,D)       True
          f0(A,B,C,D) -> f0(-1 + A,B,A,D)  [-1*A >= 0 && 9 >= A]
        Signature:
          {(f0,4);(f2,4)}
        Rule Graph:
          [0->{1},1->{1}]
    + Applied Processor:
        CloseWith False
    + Details:
        ()

NO