YES * Step 1: UnsatPaths YES + Considered Problem: Rules: 0. f0(A,B,C,D,E) -> f1(F,1,0,D,E) True (1,1) 1. f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,C,D,E) [C >= 0 && B >= 1 && A >= 101] (?,1) 2. f1(A,B,C,D,E) -> f1(11 + A,1 + B,C,D,E) [C >= 0 && B >= 1 && 100 >= A] (?,1) 3. f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,1,A,B) [C >= 0 && A >= 101 && 0 >= C && B >= 1] (?,1) 4. f1(A,B,C,D,E) -> f1(11 + A,1 + B,1,A,B) [C >= 0 && 100 >= A && 0 >= C && B >= 1] (?,1) 5. f1(A,B,C,D,E) -> f2(A,B,C,D,E) [C >= 0 && D >= A && C >= 1 && B >= E] (?,1) Signature: {(f0,5);(f1,5);(f2,5)} Flow Graph: [0->{1,2,3,4,5},1->{1,2,3,4,5},2->{1,2,3,4,5},3->{1,2,3,4,5},4->{1,2,3,4,5},5->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,5),(3,3),(3,4),(3,5),(4,3),(4,4),(4,5)] * Step 2: FromIts YES + Considered Problem: Rules: 0. f0(A,B,C,D,E) -> f1(F,1,0,D,E) True (1,1) 1. f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,C,D,E) [C >= 0 && B >= 1 && A >= 101] (?,1) 2. f1(A,B,C,D,E) -> f1(11 + A,1 + B,C,D,E) [C >= 0 && B >= 1 && 100 >= A] (?,1) 3. f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,1,A,B) [C >= 0 && A >= 101 && 0 >= C && B >= 1] (?,1) 4. f1(A,B,C,D,E) -> f1(11 + A,1 + B,1,A,B) [C >= 0 && 100 >= A && 0 >= C && B >= 1] (?,1) 5. f1(A,B,C,D,E) -> f2(A,B,C,D,E) [C >= 0 && D >= A && C >= 1 && B >= E] (?,1) Signature: {(f0,5);(f1,5);(f2,5)} Flow Graph: [0->{1,2,3,4},1->{1,2,3,4,5},2->{1,2,3,4,5},3->{1,2},4->{1,2},5->{}] + Applied Processor: FromIts + Details: () * Step 3: Decompose YES + Considered Problem: Rules: f0(A,B,C,D,E) -> f1(F,1,0,D,E) True f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,C,D,E) [C >= 0 && B >= 1 && A >= 101] f1(A,B,C,D,E) -> f1(11 + A,1 + B,C,D,E) [C >= 0 && B >= 1 && 100 >= A] f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,1,A,B) [C >= 0 && A >= 101 && 0 >= C && B >= 1] f1(A,B,C,D,E) -> f1(11 + A,1 + B,1,A,B) [C >= 0 && 100 >= A && 0 >= C && B >= 1] f1(A,B,C,D,E) -> f2(A,B,C,D,E) [C >= 0 && D >= A && C >= 1 && B >= E] Signature: {(f0,5);(f1,5);(f2,5)} Rule Graph: [0->{1,2,3,4},1->{1,2,3,4,5},2->{1,2,3,4,5},3->{1,2},4->{1,2},5->{}] + Applied Processor: Decompose NoGreedy + Details: We construct a looptree: P: [0,1,2,3,4,5] | `- p:[1,2,3,4] c: [4] | `- p:[1,2,3] c: [3] | `- p:[1,2] c: [2] | `- p:[1] c: [1] * Step 4: CloseWith YES + Considered Problem: (Rules: f0(A,B,C,D,E) -> f1(F,1,0,D,E) True f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,C,D,E) [C >= 0 && B >= 1 && A >= 101] f1(A,B,C,D,E) -> f1(11 + A,1 + B,C,D,E) [C >= 0 && B >= 1 && 100 >= A] f1(A,B,C,D,E) -> f1(-10 + A,-1 + B,1,A,B) [C >= 0 && A >= 101 && 0 >= C && B >= 1] f1(A,B,C,D,E) -> f1(11 + A,1 + B,1,A,B) [C >= 0 && 100 >= A && 0 >= C && B >= 1] f1(A,B,C,D,E) -> f2(A,B,C,D,E) [C >= 0 && D >= A && C >= 1 && B >= E] Signature: {(f0,5);(f1,5);(f2,5)} Rule Graph: [0->{1,2,3,4},1->{1,2,3,4,5},2->{1,2,3,4,5},3->{1,2},4->{1,2},5->{}] ,We construct a looptree: P: [0,1,2,3,4,5] | `- p:[1,2,3,4] c: [4] | `- p:[1,2,3] c: [3] | `- p:[1,2] c: [2] | `- p:[1] c: [1]) + Applied Processor: CloseWith True + Details: () YES