YES * Step 1: FromIts YES + Considered Problem: Rules: 0. start(A,B) -> eval(A,B) True (1,1) 1. eval(A,B) -> eval(A,-1 + B) [A >= 1 && B >= 1] (?,1) 2. eval(A,B) -> eval(-1 + A,C) [A >= 1 && B >= 1] (?,1) Signature: {(eval,2);(start,2)} Flow Graph: [0->{1,2},1->{1,2},2->{1,2}] + Applied Processor: FromIts + Details: () * Step 2: Decompose YES + Considered Problem: Rules: start(A,B) -> eval(A,B) True eval(A,B) -> eval(A,-1 + B) [A >= 1 && B >= 1] eval(A,B) -> eval(-1 + A,C) [A >= 1 && B >= 1] Signature: {(eval,2);(start,2)} Rule Graph: [0->{1,2},1->{1,2},2->{1,2}] + Applied Processor: Decompose NoGreedy + Details: We construct a looptree: P: [0,1,2] | `- p:[1,2] c: [2] | `- p:[1] c: [1] * Step 3: CloseWith YES + Considered Problem: (Rules: start(A,B) -> eval(A,B) True eval(A,B) -> eval(A,-1 + B) [A >= 1 && B >= 1] eval(A,B) -> eval(-1 + A,C) [A >= 1 && B >= 1] Signature: {(eval,2);(start,2)} Rule Graph: [0->{1,2},1->{1,2},2->{1,2}] ,We construct a looptree: P: [0,1,2] | `- p:[1,2] c: [2] | `- p:[1] c: [1]) + Applied Processor: CloseWith True + Details: () YES