MAYBE Initial complexity problem: 1: T: (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ Ar_0 >= Ar_1 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ Ar_2 >= 3 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ 1 >= Ar_2 ] (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f53(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) (Comp: ?, Cost: 1) f55(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f58(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f53(Ar_0, Ar_1, Ar_2, 0, Fresh_19, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ 0 >= Fresh_19 ] (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f53(Ar_0, Ar_1, Ar_2, 0, Fresh_18, 0, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ Fresh_18 >= 1 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f45(Ar_0, Ar_1, 2, Ar_3 + 1, Ar_4, Ar_5, Ar_7, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ Ar_2 = 2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f45(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Fresh_14, Fresh_15, Fresh_16, Fresh_17, Ar_3, Fresh_14, Fresh_14, Fresh_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f37(Ar_0, Ar_1, Fresh_9, Ar_3, Ar_4, Ar_5, Ar_6, Fresh_10, Fresh_11, Fresh_12, Fresh_13, Ar_3, Fresh_10, Fresh_10, Fresh_10, Fresh_10, Ar_17, 0, Fresh_9, Fresh_9, Fresh_9, 0, Ar_22)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f37(Ar_0, Ar_1, Fresh_4, Ar_3, Ar_4, Ar_5, Ar_6, Fresh_5, Fresh_6, Fresh_7, Fresh_8, Ar_3, Fresh_5, Fresh_5, Fresh_5, Fresh_5, Ar_17, 0, Fresh_4, Fresh_4, Fresh_4, 0, Ar_22)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f11(Ar_0 + 1, Ar_1, 1, Ar_3, Ar_4, Ar_5, Ar_6, Fresh_0, Fresh_1, Fresh_2, Fresh_3, Ar_3, Fresh_0, Fresh_0, Fresh_0, Fresh_0, Ar_17, Ar_17, 1, 1, 1, 0, Ar_22)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f11(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, 0, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, 0)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4, Ar_5, Ar_6, Ar_7, Ar_8, Ar_9, Ar_10, Ar_11, Ar_12, Ar_13, Ar_14, Ar_15, Ar_16, Ar_17, Ar_18, Ar_19, Ar_20, Ar_21, Ar_22)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Slicing away variables that do not contribute to conditions from problem 1 leaves variables [Ar_0, Ar_1, Ar_2]. We thus obtain the following problem: 2: T: (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] (Comp: ?, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: ?, Cost: 1) f55(Ar_0, Ar_1, Ar_2) -> Com_1(f58(Ar_0, Ar_1, Ar_2)) (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] start location: koat_start leaf cost: 0 Testing for reachability in the complexity graph removes the following transition from problem 2: f55(Ar_0, Ar_1, Ar_2) -> Com_1(f58(Ar_0, Ar_1, Ar_2)) We thus obtain the following problem: 3: T: (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 3 produces the following problem: 4: T: (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: ?, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 1, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 A polynomial rank function with Pol(f53) = 0 Pol(f45) = 1 Pol(f37) = 2 Pol(f11) = 3 Pol(f0) = 3 Pol(koat_start) = 3 orients all transitions weakly and the transitions f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] strictly and produces the following problem: 5: T: (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: ?, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 1, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 5 produces the following problem: 6: T: (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: ?, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 1, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 A polynomial rank function with Pol(f53) = -V_1 + V_2 Pol(f45) = -V_1 + V_2 Pol(f37) = -V_1 + V_2 Pol(f11) = -V_1 + V_2 Pol(f0) = -V_1 + V_2 Pol(koat_start) = -V_1 + V_2 orients all transitions weakly and the transition f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] strictly and produces the following problem: 7: T: (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_2 >= 3 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ Ar_2 = 2 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ 1 >= Ar_2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: Ar_0 + Ar_1, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 1, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Applied AI with 'oct' on problem 7 to obtain the following invariants: For symbol f37: -X_1 + X_2 - 1 >= 0 This yielded the following problem: 8: T: (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] (Comp: 1, Cost: 1) f0(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0, Ar_1, Ar_2)) (Comp: Ar_0 + Ar_1, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f11(Ar_0 + 1, Ar_1, 1)) [ 0 >= Fresh_0 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_4)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_5 /\ 0 >= Fresh_4 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f37(Ar_0, Ar_1, Fresh_9)) [ Ar_1 >= Ar_0 + 1 /\ 0 >= Fresh_10 /\ Fresh_9 >= 2 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Fresh_14 >= 1 /\ Ar_1 >= Ar_0 + 1 ] (Comp: 3, Cost: 1) f11(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= Ar_1 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ -Ar_0 + Ar_1 - 1 >= 0 /\ 1 >= Ar_2 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, 2)) [ -Ar_0 + Ar_1 - 1 >= 0 /\ Ar_2 = 2 ] (Comp: 3, Cost: 1) f37(Ar_0, Ar_1, Ar_2) -> Com_1(f45(Ar_0, Ar_1, Ar_2)) [ -Ar_0 + Ar_1 - 1 >= 0 /\ Ar_2 >= 3 ] (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ Fresh_18 >= 1 ] (Comp: 3, Cost: 1) f45(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) [ 0 >= Fresh_19 ] (Comp: ?, Cost: 1) f53(Ar_0, Ar_1, Ar_2) -> Com_1(f53(Ar_0, Ar_1, Ar_2)) start location: koat_start leaf cost: 0 Complexity upper bound ? Time: 2.520 sec (SMT: 2.412 sec)