YES

Problem:
 rec[revApp_0][2](Nil(),Cons(x1,x2)) -> Cons(x1,x2)
 rec[revApp_0][2](Cons(x14,x10),x6) -> rec[revApp_0][2](x10,Cons(x14,x6))
 rec[dfsAcc_0][3](Leaf(x40),x56) -> Cons(x40,x56)
 rec[dfsAcc_0][3](Node(x14,x10),x6) -> rec[dfsAcc_0][3](x10,rec[dfsAcc_0][3](x14,x6))
 main(x1) -> rec[revApp_0][2](rec[dfsAcc_0][3](x1,Nil()),Nil())

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [main](x0) = 4x0 + 4,
   
   [Node](x0, x1) = 5x0 + x1 + 2,
   
   [rec[dfsAcc_0][3]](x0, x1) = x0 + x1 + 1,
   
   [Leaf](x0) = x0 + 1,
   
   [rec[revApp_0][2]](x0, x1) = x0 + x1 + 3,
   
   [Cons](x0, x1) = x0 + x1,
   
   [Nil] = 0
  orientation:
   rec[revApp_0][2](Nil(),Cons(x1,x2)) = x1 + x2 + 3 >= x1 + x2 = Cons(x1,x2)
   
   rec[revApp_0][2](Cons(x14,x10),x6) = x10 + x14 + x6 + 3 >= x10 + x14 + x6 + 3 = rec[revApp_0][2](x10,Cons(x14,x6))
   
   rec[dfsAcc_0][3](Leaf(x40),x56) = x40 + x56 + 2 >= x40 + x56 = Cons(x40,x56)
   
   rec[dfsAcc_0][3](Node(x14,x10),x6) = x10 + 5x14 + x6 + 3 >= x10 + x14 + x6 + 2 = rec[dfsAcc_0][3](x10,rec[dfsAcc_0][3](x14,x6))
   
   main(x1) = 4x1 + 4 >= x1 + 4 = rec[revApp_0][2](rec[dfsAcc_0][3](x1,Nil()),Nil())
  problem:
   rec[revApp_0][2](Cons(x14,x10),x6) -> rec[revApp_0][2](x10,Cons(x14,x6))
   main(x1) -> rec[revApp_0][2](rec[dfsAcc_0][3](x1,Nil()),Nil())
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [main](x0) = x0 + 1,
    
    [rec[dfsAcc_0][3]](x0, x1) = x0 + x1,
    
    [rec[revApp_0][2]](x0, x1) = x0 + x1,
    
    [Cons](x0, x1) = x0 + x1 + 4,
    
    [Nil] = 0
   orientation:
    rec[revApp_0][2](Cons(x14,x10),x6) = x10 + x14 + x6 + 4 >= x10 + x14 + x6 + 4 = rec[revApp_0][2](x10,Cons(x14,x6))
    
    main(x1) = x1 + 1 >= x1 = rec[revApp_0][2](rec[dfsAcc_0][3](x1,Nil()),Nil())
   problem:
    rec[revApp_0][2](Cons(x14,x10),x6) -> rec[revApp_0][2](x10,Cons(x14,x6))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [rec[revApp_0][2]](x0, x1) = 2x0 + x1 + 2,
     
     [Cons](x0, x1) = 2x0 + x1 + 2
    orientation:
     rec[revApp_0][2](Cons(x14,x10),x6) = 2x10 + 4x14 + x6 + 6 >= 2x10 + 2x14 + x6 + 4 = rec[revApp_0][2](x10,Cons(x14,x6))
    problem:
     
    Qed