YES(?,O(1)) 0.00/0.32 YES(?,O(1)) 0.00/0.32 0.00/0.32 We are left with following problem, upon which TcT provides the 0.00/0.32 certificate YES(?,O(1)). 0.00/0.32 0.00/0.32 Strict Trs: 0.00/0.32 { f(X) -> n__f(X) 0.00/0.32 , f(f(X)) -> c(n__f(g(n__f(X)))) 0.00/0.32 , c(X) -> d(activate(X)) 0.00/0.32 , d(X) -> n__d(X) 0.00/0.32 , activate(X) -> X 0.00/0.32 , activate(n__f(X)) -> f(X) 0.00/0.32 , activate(n__d(X)) -> d(X) 0.00/0.32 , h(X) -> c(n__d(X)) } 0.00/0.32 Obligation: 0.00/0.32 innermost runtime complexity 0.00/0.32 Answer: 0.00/0.32 YES(?,O(1)) 0.00/0.32 0.00/0.32 Arguments of following rules are not normal-forms: 0.00/0.32 0.00/0.32 { f(f(X)) -> c(n__f(g(n__f(X)))) } 0.00/0.32 0.00/0.32 All above mentioned rules can be savely removed. 0.00/0.32 0.00/0.32 We are left with following problem, upon which TcT provides the 0.00/0.32 certificate YES(?,O(1)). 0.00/0.32 0.00/0.32 Strict Trs: 0.00/0.32 { f(X) -> n__f(X) 0.00/0.32 , c(X) -> d(activate(X)) 0.00/0.32 , d(X) -> n__d(X) 0.00/0.32 , activate(X) -> X 0.00/0.32 , activate(n__f(X)) -> f(X) 0.00/0.32 , activate(n__d(X)) -> d(X) 0.00/0.32 , h(X) -> c(n__d(X)) } 0.00/0.32 Obligation: 0.00/0.32 innermost runtime complexity 0.00/0.32 Answer: 0.00/0.32 YES(?,O(1)) 0.00/0.32 0.00/0.32 The input was oriented with the instance of 'Small Polynomial Path 0.00/0.32 Order (PS,0-bounded)' as induced by the safe mapping 0.00/0.32 0.00/0.32 safe(f) = {1}, safe(c) = {1}, safe(n__f) = {1}, safe(d) = {1}, 0.00/0.32 safe(activate) = {1}, safe(h) = {1}, safe(n__d) = {1} 0.00/0.32 0.00/0.32 and precedence 0.00/0.32 0.00/0.32 c > f, c > d, c > activate, activate > f, activate > d, h > f, 0.00/0.32 h > c, h > d, h > activate, f ~ d . 0.00/0.32 0.00/0.32 Following symbols are considered recursive: 0.00/0.32 0.00/0.32 {} 0.00/0.32 0.00/0.32 The recursion depth is 0. 0.00/0.32 0.00/0.32 For your convenience, here are the satisfied ordering constraints: 0.00/0.32 0.00/0.32 f(; X) > n__f(; X) 0.00/0.32 0.00/0.32 c(; X) > d(; activate(; X)) 0.00/0.32 0.00/0.32 d(; X) > n__d(; X) 0.00/0.32 0.00/0.32 activate(; X) > X 0.00/0.32 0.00/0.32 activate(; n__f(; X)) > f(; X) 0.00/0.32 0.00/0.32 activate(; n__d(; X)) > d(; X) 0.00/0.32 0.00/0.32 h(; X) > c(; n__d(; X)) 0.00/0.32 0.00/0.32 0.00/0.32 Hurray, we answered YES(?,O(1)) 0.00/0.32 EOF