YES(?,POLY) 542.65/176.53 YES(?,POLY) 542.65/176.53 542.65/176.53 We are left with following problem, upon which TcT provides the 542.65/176.53 certificate YES(?,POLY). 542.65/176.53 542.65/176.53 Strict Trs: 542.65/176.53 { f(s(x1), x2, x3, x4, x5, x6, x7, x8, x9, x10) -> 542.65/176.53 f(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), s(x2), x3, x4, x5, x6, x7, x8, x9, x10) -> 542.65/176.53 f(x2, x2, x3, x4, x5, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), s(x3), x4, x5, x6, x7, x8, x9, x10) -> 542.65/176.53 f(x3, x3, x3, x4, x5, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), s(x4), x5, x6, x7, x8, x9, x10) -> 542.65/176.53 f(x4, x4, x4, x4, x5, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), s(x5), x6, x7, x8, x9, x10) -> 542.65/176.53 f(x5, x5, x5, x5, x5, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), s(x6), x7, x8, x9, x10) -> 542.65/176.53 f(x6, x6, x6, x6, x6, x6, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), 0(), s(x7), x8, x9, x10) -> 542.65/176.53 f(x7, x7, x7, x7, x7, x7, x7, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), 0(), 0(), s(x8), x9, x10) -> 542.65/176.53 f(x8, x8, x8, x8, x8, x8, x8, x8, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), s(x9), x10) -> 542.65/176.53 f(x9, x9, x9, x9, x9, x9, x9, x9, x9, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), s(x10)) -> 542.65/176.53 f(x10, x10, x10, x10, x10, x10, x10, x10, x10, x10) 542.65/176.53 , f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0()) -> 0() } 542.65/176.53 Obligation: 542.65/176.53 innermost runtime complexity 542.65/176.53 Answer: 542.65/176.53 YES(?,POLY) 542.65/176.53 542.65/176.53 The input was oriented with the instance of 'Polynomial Path Order 542.65/176.53 (PS)' as induced by the safe mapping 542.65/176.53 542.65/176.53 safe(f) = {}, safe(s) = {1}, safe(0) = {} 542.65/176.53 542.65/176.53 and precedence 542.65/176.53 542.65/176.53 empty . 542.65/176.53 542.65/176.53 Following symbols are considered recursive: 542.65/176.53 542.65/176.53 {f} 542.65/176.53 542.65/176.53 The recursion depth is 1. 542.65/176.53 542.65/176.53 For your convenience, here are the satisfied ordering constraints: 542.65/176.53 542.65/176.53 f(s(; x1), x2, x3, x4, x5, x6, x7, x8, x9, x10;) > f(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), s(; x2), x3, x4, x5, x6, x7, x8, x9, x10;) > f(x2, x2, x3, x4, x5, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), s(; x3), x4, x5, x6, x7, x8, x9, x10;) > f(x3, x3, x3, x4, x5, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), s(; x4), x5, x6, x7, x8, x9, x10;) > f(x4, x4, x4, x4, x5, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), s(; x5), x6, x7, x8, x9, x10;) > f(x5, x5, x5, x5, x5, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), s(; x6), x7, x8, x9, x10;) > f(x6, x6, x6, x6, x6, x6, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), 0(), s(; x7), x8, x9, x10;) > f(x7, x7, x7, x7, x7, x7, x7, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), 0(), 0(), s(; x8), x9, x10;) > f(x8, x8, x8, x8, x8, x8, x8, x8, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), s(; x9), x10;) > f(x9, x9, x9, x9, x9, x9, x9, x9, x9, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), s(; x10);) > f(x10, x10, x10, x10, x10, x10, x10, x10, x10, x10;) 542.65/176.53 542.65/176.53 f(0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0(), 0();) > 0() 542.65/176.53 542.65/176.53 542.65/176.53 Hurray, we answered YES(?,POLY) 542.84/176.60 EOF