YES(O(1),O(n^1)) 61.75/24.04 YES(O(1),O(n^1)) 61.75/24.04 61.75/24.04 We are left with following problem, upon which TcT provides the 61.75/24.04 certificate YES(O(1),O(n^1)). 61.75/24.04 61.75/24.04 Strict Trs: 61.75/24.04 { implies(x, or(y, z)) -> or(y, implies(x, z)) 61.75/24.04 , implies(not(x), y) -> or(x, y) 61.75/24.04 , implies(not(x), or(y, z)) -> implies(y, or(x, z)) } 61.75/24.04 Obligation: 61.75/24.04 innermost runtime complexity 61.75/24.04 Answer: 61.75/24.04 YES(O(1),O(n^1)) 61.75/24.04 61.75/24.04 The weightgap principle applies (using the following nonconstant 61.75/24.04 growth matrix-interpretation) 61.75/24.04 61.75/24.04 The following argument positions are usable: 61.75/24.04 Uargs(or) = {2} 61.75/24.04 61.75/24.04 TcT has computed the following matrix interpretation satisfying 61.75/24.04 not(EDA) and not(IDA(1)). 61.75/24.04 61.75/24.04 [implies](x1, x2) = [1] x1 + [1] x2 + [0] 61.75/24.04 61.75/24.04 [not](x1) = [1] x1 + [4] 61.75/24.04 61.75/24.04 [or](x1, x2) = [1] x1 + [1] x2 + [0] 61.75/24.04 61.75/24.04 The order satisfies the following ordering constraints: 61.75/24.04 61.75/24.04 [implies(x, or(y, z))] = [1] x + [1] y + [1] z + [0] 61.75/24.04 >= [1] x + [1] y + [1] z + [0] 61.75/24.04 = [or(y, implies(x, z))] 61.75/24.04 61.75/24.04 [implies(not(x), y)] = [1] x + [1] y + [4] 61.75/24.04 > [1] x + [1] y + [0] 61.75/24.04 = [or(x, y)] 61.75/24.04 61.75/24.04 [implies(not(x), or(y, z))] = [1] x + [1] y + [1] z + [4] 61.75/24.04 > [1] x + [1] y + [1] z + [0] 61.75/24.04 = [implies(y, or(x, z))] 61.75/24.04 61.75/24.04 61.75/24.04 Further, it can be verified that all rules not oriented are covered by the weightgap condition. 61.75/24.04 61.75/24.04 We are left with following problem, upon which TcT provides the 61.75/24.04 certificate YES(O(1),O(n^1)). 61.75/24.04 61.75/24.04 Strict Trs: { implies(x, or(y, z)) -> or(y, implies(x, z)) } 61.75/24.04 Weak Trs: 61.75/24.04 { implies(not(x), y) -> or(x, y) 61.75/24.04 , implies(not(x), or(y, z)) -> implies(y, or(x, z)) } 61.75/24.04 Obligation: 61.75/24.04 innermost runtime complexity 61.75/24.04 Answer: 61.75/24.04 YES(O(1),O(n^1)) 61.75/24.04 61.75/24.04 We use the processor 'matrix interpretation of dimension 1' to 61.75/24.04 orient following rules strictly. 61.75/24.04 61.75/24.04 Trs: { implies(x, or(y, z)) -> or(y, implies(x, z)) } 61.75/24.04 61.75/24.04 The induced complexity on above rules (modulo remaining rules) is 61.75/24.04 YES(?,O(n^1)) . These rules are moved into the corresponding weak 61.75/24.04 component(s). 61.75/24.04 61.75/24.04 Sub-proof: 61.75/24.04 ---------- 61.75/24.04 The following argument positions are usable: 61.75/24.04 Uargs(or) = {2} 61.75/24.04 61.75/24.04 TcT has computed the following constructor-based matrix 61.75/24.04 interpretation satisfying not(EDA). 61.75/24.04 61.75/24.04 [implies](x1, x2) = [2] x1 + [2] x2 + [5] 61.75/24.04 61.75/24.04 [not](x1) = [1] x1 + [2] 61.75/24.04 61.75/24.04 [or](x1, x2) = [1] x1 + [1] x2 + [2] 61.75/24.04 61.75/24.04 The order satisfies the following ordering constraints: 61.75/24.04 61.75/24.04 [implies(x, or(y, z))] = [2] x + [2] y + [2] z + [9] 61.75/24.04 > [2] x + [1] y + [2] z + [7] 61.75/24.04 = [or(y, implies(x, z))] 61.75/24.04 61.75/24.04 [implies(not(x), y)] = [2] x + [2] y + [9] 61.75/24.04 > [1] x + [1] y + [2] 61.75/24.04 = [or(x, y)] 61.75/24.04 61.75/24.04 [implies(not(x), or(y, z))] = [2] x + [2] y + [2] z + [13] 61.75/24.04 > [2] x + [2] y + [2] z + [9] 61.75/24.04 = [implies(y, or(x, z))] 61.75/24.04 61.75/24.04 61.75/24.04 We return to the main proof. 61.75/24.04 61.75/24.04 We are left with following problem, upon which TcT provides the 61.75/24.04 certificate YES(O(1),O(1)). 61.75/24.04 61.75/24.04 Weak Trs: 61.75/24.04 { implies(x, or(y, z)) -> or(y, implies(x, z)) 61.75/24.04 , implies(not(x), y) -> or(x, y) 61.75/24.04 , implies(not(x), or(y, z)) -> implies(y, or(x, z)) } 61.75/24.04 Obligation: 61.75/24.04 innermost runtime complexity 61.75/24.04 Answer: 61.75/24.04 YES(O(1),O(1)) 61.75/24.04 61.75/24.04 Empty rules are trivially bounded 61.75/24.04 61.75/24.04 Hurray, we answered YES(O(1),O(n^1)) 61.75/24.05 EOF