YES(O(1),O(1)) 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Strict Trs: 0.00/0.03 { h(x, c(y, z), t(w)) -> h(c(s(y), x), z, t(c(t(w), w))) 0.00/0.03 , h(c(x, y), c(s(z), z), t(w)) -> 0.00/0.03 h(z, c(y, x), t(t(c(x, c(y, t(w)))))) 0.00/0.03 , h(c(s(x), c(s(0()), y)), z, t(x)) -> 0.00/0.03 h(y, c(s(0()), c(x, z)), t(t(c(x, s(x))))) 0.00/0.03 , t(x) -> x 0.00/0.03 , t(x) -> c(0(), c(0(), c(0(), c(0(), c(0(), x))))) 0.00/0.03 , t(t(x)) -> t(c(t(x), x)) } 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 Arguments of following rules are not normal-forms: 0.00/0.03 0.00/0.03 { h(x, c(y, z), t(w)) -> h(c(s(y), x), z, t(c(t(w), w))) 0.00/0.03 , h(c(x, y), c(s(z), z), t(w)) -> 0.00/0.03 h(z, c(y, x), t(t(c(x, c(y, t(w)))))) 0.00/0.03 , h(c(s(x), c(s(0()), y)), z, t(x)) -> 0.00/0.03 h(y, c(s(0()), c(x, z)), t(t(c(x, s(x))))) 0.00/0.03 , t(t(x)) -> t(c(t(x), x)) } 0.00/0.03 0.00/0.03 All above mentioned rules can be savely removed. 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Strict Trs: 0.00/0.03 { t(x) -> x 0.00/0.03 , t(x) -> c(0(), c(0(), c(0(), c(0(), c(0(), x))))) } 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 We add the following weak dependency pairs: 0.00/0.03 0.00/0.03 Strict DPs: 0.00/0.03 { t^#(x) -> c_1() 0.00/0.03 , t^#(x) -> c_2() } 0.00/0.03 0.00/0.03 and mark the set of starting terms. 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Strict DPs: 0.00/0.03 { t^#(x) -> c_1() 0.00/0.03 , t^#(x) -> c_2() } 0.00/0.03 Strict Trs: 0.00/0.03 { t(x) -> x 0.00/0.03 , t(x) -> c(0(), c(0(), c(0(), c(0(), c(0(), x))))) } 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 No rule is usable, rules are removed from the input problem. 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Strict DPs: 0.00/0.03 { t^#(x) -> c_1() 0.00/0.03 , t^#(x) -> c_2() } 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 The weightgap principle applies (using the following constant 0.00/0.03 growth matrix-interpretation) 0.00/0.03 0.00/0.03 The following argument positions are usable: 0.00/0.03 none 0.00/0.03 0.00/0.03 TcT has computed the following constructor-restricted matrix 0.00/0.03 interpretation. 0.00/0.03 0.00/0.03 [t^#](x1) = [2] 0.00/0.03 [2] 0.00/0.03 0.00/0.03 [c_1] = [1] 0.00/0.03 [2] 0.00/0.03 0.00/0.03 [c_2] = [1] 0.00/0.03 [1] 0.00/0.03 0.00/0.03 The order satisfies the following ordering constraints: 0.00/0.03 0.00/0.03 [t^#(x)] = [2] 0.00/0.03 [2] 0.00/0.03 > [1] 0.00/0.03 [2] 0.00/0.03 = [c_1()] 0.00/0.03 0.00/0.03 [t^#(x)] = [2] 0.00/0.03 [2] 0.00/0.03 > [1] 0.00/0.03 [1] 0.00/0.03 = [c_2()] 0.00/0.03 0.00/0.03 0.00/0.03 Further, it can be verified that all rules not oriented are covered by the weightgap condition. 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Weak DPs: 0.00/0.03 { t^#(x) -> c_1() 0.00/0.03 , t^#(x) -> c_2() } 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 The following weak DPs constitute a sub-graph of the DG that is 0.00/0.03 closed under successors. The DPs are removed. 0.00/0.03 0.00/0.03 { t^#(x) -> c_1() 0.00/0.03 , t^#(x) -> c_2() } 0.00/0.03 0.00/0.03 We are left with following problem, upon which TcT provides the 0.00/0.03 certificate YES(O(1),O(1)). 0.00/0.03 0.00/0.03 Rules: Empty 0.00/0.03 Obligation: 0.00/0.03 innermost runtime complexity 0.00/0.03 Answer: 0.00/0.03 YES(O(1),O(1)) 0.00/0.03 0.00/0.03 Empty rules are trivially bounded 0.00/0.03 0.00/0.03 Hurray, we answered YES(O(1),O(1)) 0.00/0.03 EOF