YES(O(1), O(1)) 0.00/0.96 YES(O(1), O(1)) 0.00/0.98 0.00/0.98 0.00/0.98 0.00/0.98 0.00/0.98 0.00/0.98 Runtime Complexity (innermost) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml.xml 0.00/0.98 0.00/0.98 0.00/0.98
0.00/0.98 0.00/0.98 0.00/0.98
0.00/0.98
0.00/0.98

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(X)) → X

Rewrite Strategy: INNERMOST
0.00/0.98
0.00/0.98

(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT
0.00/0.98
0.00/0.98

(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(z0)) → z0
Tuples:

F(s(0)) → c1(F(p(s(0))), P(s(0)))
S tuples:

F(s(0)) → c1(F(p(s(0))), P(s(0)))
K tuples:none
Defined Rule Symbols:

f, p

Defined Pair Symbols:

F

Compound Symbols:

c1

0.00/0.98
0.00/0.98

(3) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts
0.00/0.98
0.00/0.98

(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(z0)) → z0
Tuples:

F(s(0)) → c1(F(p(s(0))))
S tuples:

F(s(0)) → c1(F(p(s(0))))
K tuples:none
Defined Rule Symbols:

f, p

Defined Pair Symbols:

F

Compound Symbols:

c1

0.00/0.98
0.00/0.98

(5) CdtNarrowingProof (BOTH BOUNDS(ID, ID) transformation)

Use narrowing to replace F(s(0)) → c1(F(p(s(0)))) by

F(s(0)) → c1(F(0))
0.00/0.98
0.00/0.98

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(z0)) → z0
Tuples:

F(s(0)) → c1(F(0))
S tuples:

F(s(0)) → c1(F(0))
K tuples:none
Defined Rule Symbols:

f, p

Defined Pair Symbols:

F

Compound Symbols:

c1

0.00/0.98
0.00/0.98

(7) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts
0.00/0.98
0.00/0.98

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(z0)) → z0
Tuples:

F(s(0)) → c1
S tuples:

F(s(0)) → c1
K tuples:none
Defined Rule Symbols:

f, p

Defined Pair Symbols:

F

Compound Symbols:

c1

0.00/0.98
0.00/0.98

(9) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing nodes:

F(s(0)) → c1
0.00/0.98
0.00/0.98

(10) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → cons(0) 0.00/0.98
f(s(0)) → f(p(s(0))) 0.00/0.98
p(s(z0)) → z0
Tuples:none
S tuples:none
K tuples:none
Defined Rule Symbols:

f, p

Defined Pair Symbols:none

Compound Symbols:none

0.00/0.98
0.00/0.98

(11) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty
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0.00/0.98

(12) BOUNDS(O(1), O(1))

0.00/0.98
0.00/0.98
0.00/1.00 EOF