YES(O(1), O(n^1)) 0.00/0.81 YES(O(1), O(n^1)) 0.00/0.84 0.00/0.84 0.00/0.84
0.00/0.84 0.00/0.840 CpxTRS0.00/0.84
↳1 CpxTrsToCdtProof (BOTH BOUNDS(ID, ID))0.00/0.84
↳2 CdtProblem0.00/0.84
↳3 CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID))0.00/0.84
↳4 CdtProblem0.00/0.84
↳5 CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))))0.00/0.84
↳6 CdtProblem0.00/0.84
↳7 CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))))0.00/0.84
↳8 CdtProblem0.00/0.84
↳9 SIsEmptyProof (BOTH BOUNDS(ID, ID))0.00/0.84
↳10 BOUNDS(O(1), O(1))0.00/0.84
f(a) → b 0.00/0.84
f(c) → d 0.00/0.84
f(g(x, y)) → g(f(x), f(y)) 0.00/0.84
f(h(x, y)) → g(h(y, f(x)), h(x, f(y))) 0.00/0.84
g(x, x) → h(e, x)
Tuples:
f(a) → b 0.00/0.84
f(c) → d 0.00/0.84
f(g(z0, z1)) → g(f(z0), f(z1)) 0.00/0.84
f(h(z0, z1)) → g(h(z1, f(z0)), h(z0, f(z1))) 0.00/0.84
g(z0, z0) → h(e, z0)
S tuples:
F(g(z0, z1)) → c3(G(f(z0), f(z1)), F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(G(h(z1, f(z0)), h(z0, f(z1))), F(z0), F(z1))
K tuples:none
F(g(z0, z1)) → c3(G(f(z0), f(z1)), F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(G(h(z1, f(z0)), h(z0, f(z1))), F(z0), F(z1))
f, g
F
c3, c4
Tuples:
f(a) → b 0.00/0.84
f(c) → d 0.00/0.84
f(g(z0, z1)) → g(f(z0), f(z1)) 0.00/0.84
f(h(z0, z1)) → g(h(z1, f(z0)), h(z0, f(z1))) 0.00/0.84
g(z0, z0) → h(e, z0)
S tuples:
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
K tuples:none
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
f, g
F
c3, c4
We considered the (Usable) Rules:none
F(g(z0, z1)) → c3(F(z0), F(z1))
The order we found is given by the following interpretation:
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
POL(F(x1)) = [2]x1 0.00/0.84
POL(c3(x1, x2)) = x1 + x2 0.00/0.84
POL(c4(x1, x2)) = x1 + x2 0.00/0.84
POL(g(x1, x2)) = [3] + [4]x1 + [2]x2 0.00/0.84
POL(h(x1, x2)) = x1 + x2
Tuples:
f(a) → b 0.00/0.84
f(c) → d 0.00/0.84
f(g(z0, z1)) → g(f(z0), f(z1)) 0.00/0.84
f(h(z0, z1)) → g(h(z1, f(z0)), h(z0, f(z1))) 0.00/0.84
g(z0, z0) → h(e, z0)
S tuples:
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
K tuples:
F(h(z0, z1)) → c4(F(z0), F(z1))
Defined Rule Symbols:
F(g(z0, z1)) → c3(F(z0), F(z1))
f, g
F
c3, c4
We considered the (Usable) Rules:none
F(h(z0, z1)) → c4(F(z0), F(z1))
The order we found is given by the following interpretation:
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
POL(F(x1)) = x1 0.00/0.84
POL(c3(x1, x2)) = x1 + x2 0.00/0.84
POL(c4(x1, x2)) = x1 + x2 0.00/0.84
POL(g(x1, x2)) = [4]x1 + [4]x2 0.00/0.84
POL(h(x1, x2)) = [1] + x1 + x2
Tuples:
f(a) → b 0.00/0.84
f(c) → d 0.00/0.84
f(g(z0, z1)) → g(f(z0), f(z1)) 0.00/0.84
f(h(z0, z1)) → g(h(z1, f(z0)), h(z0, f(z1))) 0.00/0.84
g(z0, z0) → h(e, z0)
S tuples:none
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
Defined Rule Symbols:
F(g(z0, z1)) → c3(F(z0), F(z1)) 0.00/0.84
F(h(z0, z1)) → c4(F(z0), F(z1))
f, g
F
c3, c4