YES(O(1), O(n^1)) 0.00/0.76 YES(O(1), O(n^1)) 0.00/0.77 0.00/0.77 0.00/0.77
0.00/0.77 0.00/0.770 CpxTRS0.00/0.77
↳1 CpxTrsToCdtProof (BOTH BOUNDS(ID, ID))0.00/0.77
↳2 CdtProblem0.00/0.77
↳3 CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))))0.00/0.77
↳4 CdtProblem0.00/0.77
↳5 SIsEmptyProof (BOTH BOUNDS(ID, ID))0.00/0.77
↳6 BOUNDS(O(1), O(1))0.00/0.77
and(not(not(x)), y, not(z)) → and(y, band(x, z), x)
Tuples:
and(not(not(z0)), z1, not(z2)) → and(z1, band(z0, z2), z0)
S tuples:
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
K tuples:none
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
and
AND
c
We considered the (Usable) Rules:none
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
The order we found is given by the following interpretation:
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
POL(AND(x1, x2, x3)) = [4]x1 + [4]x2 0.00/0.77
POL(band(x1, x2)) = 0 0.00/0.77
POL(c(x1)) = x1 0.00/0.77
POL(not(x1)) = [4] + x1
Tuples:
and(not(not(z0)), z1, not(z2)) → and(z1, band(z0, z2), z0)
S tuples:none
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
Defined Rule Symbols:
AND(not(not(z0)), z1, not(z2)) → c(AND(z1, band(z0, z2), z0))
and
AND
c