YES(O(1), O(n^2)) 3.61/1.39 YES(O(1), O(n^2)) 3.99/1.41 3.99/1.41 3.99/1.41 3.99/1.41 3.99/1.42 3.99/1.42 Runtime Complexity (innermost) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml.xml 3.99/1.42 3.99/1.42 3.99/1.42
3.99/1.42 3.99/1.42 3.99/1.42
3.99/1.42
3.99/1.42

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

f(0) → 1 3.99/1.42
f(s(x)) → g(x, s(x)) 3.99/1.42
g(0, y) → y 3.99/1.42
g(s(x), y) → g(x, +(y, s(x))) 3.99/1.42
+(x, 0) → x 3.99/1.42
+(x, s(y)) → s(+(x, y)) 3.99/1.42
g(s(x), y) → g(x, s(+(y, x)))

Rewrite Strategy: INNERMOST
3.99/1.42
3.99/1.42

(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT
3.99/1.42
3.99/1.42

(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → 1 3.99/1.42
f(s(z0)) → g(z0, s(z0)) 3.99/1.42
g(0, z0) → z0 3.99/1.42
g(s(z0), z1) → g(z0, +(z1, s(z0))) 3.99/1.42
g(s(z0), z1) → g(z0, s(+(z1, z0))) 3.99/1.42
+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
Tuples:

F(s(z0)) → c1(G(z0, s(z0))) 3.99/1.42
G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
S tuples:

F(s(z0)) → c1(G(z0, s(z0))) 3.99/1.42
G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
K tuples:none
Defined Rule Symbols:

f, g, +

Defined Pair Symbols:

F, G, +'

Compound Symbols:

c1, c3, c4, c6

3.99/1.42
3.99/1.42

(3) CdtLeafRemovalProof (ComplexityIfPolyImplication transformation)

Removed 1 leading nodes:

F(s(z0)) → c1(G(z0, s(z0)))
3.99/1.42
3.99/1.42

(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → 1 3.99/1.42
f(s(z0)) → g(z0, s(z0)) 3.99/1.42
g(0, z0) → z0 3.99/1.42
g(s(z0), z1) → g(z0, +(z1, s(z0))) 3.99/1.42
g(s(z0), z1) → g(z0, s(+(z1, z0))) 3.99/1.42
+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
Tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
S tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
K tuples:none
Defined Rule Symbols:

f, g, +

Defined Pair Symbols:

G, +'

Compound Symbols:

c3, c4, c6

3.99/1.42
3.99/1.42

(5) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0))
We considered the (Usable) Rules:

+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
And the Tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
The order we found is given by the following interpretation:
Polynomial interpretation : 3.99/1.42

POL(+(x1, x2)) = [5] + [3]x2    3.99/1.42
POL(+'(x1, x2)) = [3]    3.99/1.42
POL(0) = 0    3.99/1.42
POL(G(x1, x2)) = [2]x1    3.99/1.42
POL(c3(x1, x2)) = x1 + x2    3.99/1.42
POL(c4(x1, x2)) = x1 + x2    3.99/1.42
POL(c6(x1)) = x1    3.99/1.42
POL(s(x1)) = [3] + x1   
3.99/1.42
3.99/1.42

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → 1 3.99/1.42
f(s(z0)) → g(z0, s(z0)) 3.99/1.42
g(0, z0) → z0 3.99/1.42
g(s(z0), z1) → g(z0, +(z1, s(z0))) 3.99/1.42
g(s(z0), z1) → g(z0, s(+(z1, z0))) 3.99/1.42
+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
Tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
S tuples:

+'(z0, s(z1)) → c6(+'(z0, z1))
K tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0))
Defined Rule Symbols:

f, g, +

Defined Pair Symbols:

G, +'

Compound Symbols:

c3, c4, c6

3.99/1.42
3.99/1.42

(7) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^2))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

+'(z0, s(z1)) → c6(+'(z0, z1))
We considered the (Usable) Rules:

+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
And the Tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
The order we found is given by the following interpretation:
Polynomial interpretation : 3.99/1.42

POL(+(x1, x2)) = [2] + [2]x22    3.99/1.42
POL(+'(x1, x2)) = x2    3.99/1.42
POL(0) = [3]    3.99/1.42
POL(G(x1, x2)) = x12    3.99/1.42
POL(c3(x1, x2)) = x1 + x2    3.99/1.42
POL(c4(x1, x2)) = x1 + x2    3.99/1.42
POL(c6(x1)) = x1    3.99/1.42
POL(s(x1)) = [2] + x1   
3.99/1.42
3.99/1.42

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(0) → 1 3.99/1.42
f(s(z0)) → g(z0, s(z0)) 3.99/1.42
g(0, z0) → z0 3.99/1.42
g(s(z0), z1) → g(z0, +(z1, s(z0))) 3.99/1.42
g(s(z0), z1) → g(z0, s(+(z1, z0))) 3.99/1.42
+(z0, 0) → z0 3.99/1.42
+(z0, s(z1)) → s(+(z0, z1))
Tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
S tuples:none
K tuples:

G(s(z0), z1) → c3(G(z0, +(z1, s(z0))), +'(z1, s(z0))) 3.99/1.42
G(s(z0), z1) → c4(G(z0, s(+(z1, z0))), +'(z1, z0)) 3.99/1.42
+'(z0, s(z1)) → c6(+'(z0, z1))
Defined Rule Symbols:

f, g, +

Defined Pair Symbols:

G, +'

Compound Symbols:

c3, c4, c6

3.99/1.42
3.99/1.42

(9) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty
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3.99/1.42

(10) BOUNDS(O(1), O(1))

3.99/1.42
3.99/1.42
3.99/1.46 EOF