YES(O(1), O(n^1)) 0.00/0.69 YES(O(1), O(n^1)) 0.00/0.70 0.00/0.70 0.00/0.70
0.00/0.70 0.00/0.700 CpxRelTRS0.00/0.70
↳1 CpxRelTrsToCDT (UPPER BOUND (ID))0.00/0.70
↳2 CdtProblem0.00/0.70
↳3 CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID))0.00/0.70
↳4 CdtProblem0.00/0.70
↳5 CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))))0.00/0.70
↳6 CdtProblem0.00/0.70
↳7 SIsEmptyProof (BOTH BOUNDS(ID, ID))0.00/0.70
↳8 BOUNDS(O(1), O(1))0.00/0.70
add0(S(x), x2) → +(S(0), add0(x2, x)) 0.00/0.70
add0(0, x2) → x2
+(x, S(0)) → S(x) 0.00/0.70
+(S(0), y) → S(y)
Tuples:
+(z0, S(0)) → S(z0) 0.00/0.70
+(S(0), z0) → S(z0) 0.00/0.70
add0(S(z0), z1) → +(S(0), add0(z1, z0)) 0.00/0.70
add0(0, z0) → z0
S tuples:
ADD0(S(z0), z1) → c2(+'(S(0), add0(z1, z0)), ADD0(z1, z0))
K tuples:none
ADD0(S(z0), z1) → c2(+'(S(0), add0(z1, z0)), ADD0(z1, z0))
add0, +
ADD0
c2
Tuples:
+(z0, S(0)) → S(z0) 0.00/0.70
+(S(0), z0) → S(z0) 0.00/0.70
add0(S(z0), z1) → +(S(0), add0(z1, z0)) 0.00/0.70
add0(0, z0) → z0
S tuples:
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
K tuples:none
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
add0, +
ADD0
c2
We considered the (Usable) Rules:none
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
The order we found is given by the following interpretation:
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
POL(ADD0(x1, x2)) = [5]x1 + [5]x2 0.00/0.70
POL(S(x1)) = [1] + x1 0.00/0.70
POL(c2(x1)) = x1
Tuples:
+(z0, S(0)) → S(z0) 0.00/0.70
+(S(0), z0) → S(z0) 0.00/0.70
add0(S(z0), z1) → +(S(0), add0(z1, z0)) 0.00/0.70
add0(0, z0) → z0
S tuples:none
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
Defined Rule Symbols:
ADD0(S(z0), z1) → c2(ADD0(z1, z0))
add0, +
ADD0
c2