YES(O(1), O(n^1)) 0.00/0.70 YES(O(1), O(n^1)) 0.00/0.71 0.00/0.71 0.00/0.71 0.00/0.71 0.00/0.71 0.00/0.71 Runtime Complexity (innermost) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml.xml 0.00/0.71 0.00/0.71 0.00/0.71
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(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

duplicate(Cons(x, xs)) → Cons(x, Cons(x, duplicate(xs))) 0.00/0.71
duplicate(Nil) → Nil 0.00/0.71
goal(x) → duplicate(x)

Rewrite Strategy: INNERMOST
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(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT
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(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

duplicate(Cons(z0, z1)) → Cons(z0, Cons(z0, duplicate(z1))) 0.00/0.71
duplicate(Nil) → Nil 0.00/0.71
goal(z0) → duplicate(z0)
Tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1)) 0.00/0.71
GOAL(z0) → c2(DUPLICATE(z0))
S tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1)) 0.00/0.71
GOAL(z0) → c2(DUPLICATE(z0))
K tuples:none
Defined Rule Symbols:

duplicate, goal

Defined Pair Symbols:

DUPLICATE, GOAL

Compound Symbols:

c, c2

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(3) CdtLeafRemovalProof (ComplexityIfPolyImplication transformation)

Removed 1 leading nodes:

GOAL(z0) → c2(DUPLICATE(z0))
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(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

duplicate(Cons(z0, z1)) → Cons(z0, Cons(z0, duplicate(z1))) 0.00/0.71
duplicate(Nil) → Nil 0.00/0.71
goal(z0) → duplicate(z0)
Tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
S tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
K tuples:none
Defined Rule Symbols:

duplicate, goal

Defined Pair Symbols:

DUPLICATE

Compound Symbols:

c

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(5) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
We considered the (Usable) Rules:none
And the Tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
The order we found is given by the following interpretation:
Polynomial interpretation : 0.00/0.71

POL(Cons(x1, x2)) = [1] + x2    0.00/0.71
POL(DUPLICATE(x1)) = [3]x1    0.00/0.71
POL(c(x1)) = x1   
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(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

duplicate(Cons(z0, z1)) → Cons(z0, Cons(z0, duplicate(z1))) 0.00/0.71
duplicate(Nil) → Nil 0.00/0.71
goal(z0) → duplicate(z0)
Tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
S tuples:none
K tuples:

DUPLICATE(Cons(z0, z1)) → c(DUPLICATE(z1))
Defined Rule Symbols:

duplicate, goal

Defined Pair Symbols:

DUPLICATE

Compound Symbols:

c

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(7) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty
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(8) BOUNDS(O(1), O(1))

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0.00/0.73 EOF