YES(O(1), O(n^1)) 0.00/0.86 YES(O(1), O(n^1)) 0.00/0.87 0.00/0.87 0.00/0.87
0.00/0.87 0.00/0.870 CpxTRS0.00/0.87
↳1 CpxTrsToCdtProof (BOTH BOUNDS(ID, ID))0.00/0.87
↳2 CdtProblem0.00/0.87
↳3 CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID))0.00/0.87
↳4 CdtProblem0.00/0.87
↳5 CdtNarrowingProof (BOTH BOUNDS(ID, ID))0.00/0.87
↳6 CdtProblem0.00/0.87
↳7 CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))))0.00/0.87
↳8 CdtProblem0.00/0.87
↳9 SIsEmptyProof (BOTH BOUNDS(ID, ID))0.00/0.87
↳10 BOUNDS(O(1), O(1))0.00/0.87
p(s(x)) → x 0.00/0.87
fac(0) → s(0) 0.00/0.87
fac(s(x)) → times(s(x), fac(p(s(x))))
Tuples:
p(s(z0)) → z0 0.00/0.87
fac(0) → s(0) 0.00/0.87
fac(s(z0)) → times(s(z0), fac(p(s(z0))))
S tuples:
FAC(s(z0)) → c2(FAC(p(s(z0))), P(s(z0)))
K tuples:none
FAC(s(z0)) → c2(FAC(p(s(z0))), P(s(z0)))
p, fac
FAC
c2
Tuples:
p(s(z0)) → z0 0.00/0.87
fac(0) → s(0) 0.00/0.87
fac(s(z0)) → times(s(z0), fac(p(s(z0))))
S tuples:
FAC(s(z0)) → c2(FAC(p(s(z0))))
K tuples:none
FAC(s(z0)) → c2(FAC(p(s(z0))))
p, fac
FAC
c2
FAC(s(z0)) → c2(FAC(z0))
Tuples:
p(s(z0)) → z0 0.00/0.87
fac(0) → s(0) 0.00/0.87
fac(s(z0)) → times(s(z0), fac(p(s(z0))))
S tuples:
FAC(s(z0)) → c2(FAC(z0))
K tuples:none
FAC(s(z0)) → c2(FAC(z0))
p, fac
FAC
c2
We considered the (Usable) Rules:none
FAC(s(z0)) → c2(FAC(z0))
The order we found is given by the following interpretation:
FAC(s(z0)) → c2(FAC(z0))
POL(FAC(x1)) = [3]x1 0.00/0.87
POL(c2(x1)) = x1 0.00/0.87
POL(s(x1)) = [1] + x1
Tuples:
p(s(z0)) → z0 0.00/0.87
fac(0) → s(0) 0.00/0.87
fac(s(z0)) → times(s(z0), fac(p(s(z0))))
S tuples:none
FAC(s(z0)) → c2(FAC(z0))
Defined Rule Symbols:
FAC(s(z0)) → c2(FAC(z0))
p, fac
FAC
c2