YES(O(1), O(n^1)) 0.00/0.75 YES(O(1), O(n^1)) 0.00/0.77 0.00/0.77 0.00/0.77 0.00/0.77 0.00/0.77 0.00/0.77 Runtime Complexity (innermost) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml.xml 0.00/0.77 0.00/0.77 0.00/0.77
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(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

not(true) → false 0.00/0.77
not(false) → true 0.00/0.77
evenodd(x, 0) → not(evenodd(x, s(0))) 0.00/0.77
evenodd(0, s(0)) → false 0.00/0.77
evenodd(s(x), s(0)) → evenodd(x, 0)

Rewrite Strategy: INNERMOST
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(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT
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(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

not(true) → false 0.00/0.77
not(false) → true 0.00/0.77
evenodd(z0, 0) → not(evenodd(z0, s(0))) 0.00/0.77
evenodd(0, s(0)) → false 0.00/0.77
evenodd(s(z0), s(0)) → evenodd(z0, 0)
Tuples:

EVENODD(z0, 0) → c2(NOT(evenodd(z0, s(0))), EVENODD(z0, s(0))) 0.00/0.77
EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0))
S tuples:

EVENODD(z0, 0) → c2(NOT(evenodd(z0, s(0))), EVENODD(z0, s(0))) 0.00/0.77
EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0))
K tuples:none
Defined Rule Symbols:

not, evenodd

Defined Pair Symbols:

EVENODD

Compound Symbols:

c2, c4

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(3) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts
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(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

not(true) → false 0.00/0.77
not(false) → true 0.00/0.77
evenodd(z0, 0) → not(evenodd(z0, s(0))) 0.00/0.77
evenodd(0, s(0)) → false 0.00/0.77
evenodd(s(z0), s(0)) → evenodd(z0, 0)
Tuples:

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0)) 0.00/0.77
EVENODD(z0, 0) → c2(EVENODD(z0, s(0)))
S tuples:

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0)) 0.00/0.77
EVENODD(z0, 0) → c2(EVENODD(z0, s(0)))
K tuples:none
Defined Rule Symbols:

not, evenodd

Defined Pair Symbols:

EVENODD

Compound Symbols:

c4, c2

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(5) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0))
We considered the (Usable) Rules:none
And the Tuples:

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0)) 0.00/0.77
EVENODD(z0, 0) → c2(EVENODD(z0, s(0)))
The order we found is given by the following interpretation:
Polynomial interpretation : 0.00/0.77

POL(0) = 0    0.00/0.77
POL(EVENODD(x1, x2)) = [2]x1    0.00/0.77
POL(c2(x1)) = x1    0.00/0.77
POL(c4(x1)) = x1    0.00/0.77
POL(s(x1)) = [1] + x1   
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(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

not(true) → false 0.00/0.77
not(false) → true 0.00/0.77
evenodd(z0, 0) → not(evenodd(z0, s(0))) 0.00/0.77
evenodd(0, s(0)) → false 0.00/0.77
evenodd(s(z0), s(0)) → evenodd(z0, 0)
Tuples:

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0)) 0.00/0.77
EVENODD(z0, 0) → c2(EVENODD(z0, s(0)))
S tuples:

EVENODD(z0, 0) → c2(EVENODD(z0, s(0)))
K tuples:

EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0))
Defined Rule Symbols:

not, evenodd

Defined Pair Symbols:

EVENODD

Compound Symbols:

c4, c2

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(7) CdtKnowledgeProof (EQUIVALENT transformation)

The following tuples could be moved from S to K by knowledge propagation:

EVENODD(z0, 0) → c2(EVENODD(z0, s(0))) 0.00/0.77
EVENODD(s(z0), s(0)) → c4(EVENODD(z0, 0))
Now S is empty
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(8) BOUNDS(O(1), O(1))

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0.00/0.78 EOF