YES(?,O(n^1)) 0.00/0.81 YES(?,O(n^1)) 0.00/0.81 0.00/0.81 We are left with following problem, upon which TcT provides the 0.00/0.81 certificate YES(?,O(n^1)). 0.00/0.81 0.00/0.81 Strict Trs: 0.00/0.81 { g(x, s(y)) -> g(f(x, y), 0()) 0.00/0.81 , g(0(), f(x, x)) -> x 0.00/0.81 , g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0())) 0.00/0.81 , g(s(x), y) -> g(f(x, y), 0()) } 0.00/0.81 Obligation: 0.00/0.81 runtime complexity 0.00/0.81 Answer: 0.00/0.81 YES(?,O(n^1)) 0.00/0.81 0.00/0.81 The input is overlay and right-linear. Switching to innermost 0.00/0.81 rewriting. 0.00/0.81 0.00/0.81 We are left with following problem, upon which TcT provides the 0.00/0.81 certificate YES(?,O(n^1)). 0.00/0.81 0.00/0.81 Strict Trs: 0.00/0.81 { g(x, s(y)) -> g(f(x, y), 0()) 0.00/0.81 , g(0(), f(x, x)) -> x 0.00/0.81 , g(f(x, y), 0()) -> f(g(x, 0()), g(y, 0())) 0.00/0.81 , g(s(x), y) -> g(f(x, y), 0()) } 0.00/0.81 Obligation: 0.00/0.81 innermost runtime complexity 0.00/0.81 Answer: 0.00/0.81 YES(?,O(n^1)) 0.00/0.81 0.00/0.81 The problem is match-bounded by 2. The enriched problem is 0.00/0.81 compatible with the following automaton. 0.00/0.81 { g_0(2, 2) -> 1 0.00/0.81 , g_1(2, 4) -> 5 0.00/0.81 , g_1(2, 4) -> 6 0.00/0.81 , g_1(3, 4) -> 1 0.00/0.81 , g_1(4, 4) -> 6 0.00/0.81 , g_1(11, 4) -> 7 0.00/0.81 , g_1(12, 4) -> 8 0.00/0.81 , g_2(2, 9) -> 7 0.00/0.81 , g_2(2, 10) -> 8 0.00/0.81 , g_2(4, 10) -> 13 0.00/0.81 , g_2(9, 10) -> 13 0.00/0.81 , g_2(10, 10) -> 13 0.00/0.81 , 0_0() -> 1 0.00/0.81 , 0_0() -> 2 0.00/0.81 , 0_1() -> 4 0.00/0.81 , 0_2() -> 9 0.00/0.81 , 0_2() -> 10 0.00/0.81 , f_0(2, 2) -> 1 0.00/0.81 , f_0(2, 2) -> 2 0.00/0.81 , f_1(2, 2) -> 3 0.00/0.81 , f_1(2, 4) -> 1 0.00/0.81 , f_1(2, 4) -> 2 0.00/0.81 , f_1(2, 9) -> 11 0.00/0.81 , f_1(2, 10) -> 12 0.00/0.81 , f_1(5, 6) -> 1 0.00/0.81 , f_1(6, 6) -> 5 0.00/0.81 , f_1(6, 6) -> 6 0.00/0.81 , f_1(6, 6) -> 7 0.00/0.81 , f_1(6, 6) -> 8 0.00/0.81 , f_2(7, 8) -> 1 0.00/0.81 , f_2(8, 13) -> 5 0.00/0.81 , f_2(8, 13) -> 6 0.00/0.81 , f_2(8, 13) -> 7 0.00/0.81 , f_2(8, 13) -> 8 0.00/0.81 , s_0(2) -> 1 0.00/0.81 , s_0(2) -> 2 } 0.00/0.81 0.00/0.81 Hurray, we answered YES(?,O(n^1)) 0.00/0.81 EOF