YES(?,O(n^1))
0.00/0.89	YES(?,O(n^1))
0.00/0.89	
0.00/0.89	We are left with following problem, upon which TcT provides the
0.00/0.89	certificate YES(?,O(n^1)).
0.00/0.89	
0.00/0.89	Strict Trs:
0.00/0.89	  { not(true()) -> false()
0.00/0.89	  , not(false()) -> true()
0.00/0.89	  , evenodd(x, 0()) -> not(evenodd(x, s(0())))
0.00/0.89	  , evenodd(0(), s(0())) -> false()
0.00/0.89	  , evenodd(s(x), s(0())) -> evenodd(x, 0()) }
0.00/0.89	Obligation:
0.00/0.89	  runtime complexity
0.00/0.89	Answer:
0.00/0.89	  YES(?,O(n^1))
0.00/0.89	
0.00/0.89	The input is overlay and right-linear. Switching to innermost
0.00/0.89	rewriting.
0.00/0.89	
0.00/0.89	We are left with following problem, upon which TcT provides the
0.00/0.89	certificate YES(?,O(n^1)).
0.00/0.89	
0.00/0.89	Strict Trs:
0.00/0.89	  { not(true()) -> false()
0.00/0.89	  , not(false()) -> true()
0.00/0.89	  , evenodd(x, 0()) -> not(evenodd(x, s(0())))
0.00/0.89	  , evenodd(0(), s(0())) -> false()
0.00/0.89	  , evenodd(s(x), s(0())) -> evenodd(x, 0()) }
0.00/0.89	Obligation:
0.00/0.89	  innermost runtime complexity
0.00/0.89	Answer:
0.00/0.89	  YES(?,O(n^1))
0.00/0.89	
0.00/0.89	The problem is match-bounded by 3. The enriched problem is
0.00/0.89	compatible with the following automaton.
0.00/0.89	{ not_0(2) -> 1
0.00/0.89	, not_1(3) -> 1
0.00/0.89	, not_2(6) -> 1
0.00/0.89	, not_2(6) -> 3
0.00/0.89	, not_2(6) -> 6
0.00/0.89	, true_0() -> 2
0.00/0.89	, true_1() -> 1
0.00/0.89	, true_2() -> 1
0.00/0.89	, true_2() -> 3
0.00/0.89	, true_2() -> 6
0.00/0.89	, true_3() -> 1
0.00/0.89	, true_3() -> 3
0.00/0.89	, true_3() -> 6
0.00/0.89	, false_0() -> 2
0.00/0.89	, false_1() -> 1
0.00/0.89	, false_1() -> 3
0.00/0.89	, false_1() -> 6
0.00/0.89	, false_2() -> 1
0.00/0.89	, false_3() -> 1
0.00/0.89	, false_3() -> 3
0.00/0.89	, false_3() -> 6
0.00/0.89	, evenodd_0(2, 2) -> 1
0.00/0.89	, evenodd_1(2, 4) -> 3
0.00/0.89	, evenodd_1(2, 5) -> 1
0.00/0.89	, evenodd_1(2, 5) -> 3
0.00/0.89	, evenodd_1(2, 5) -> 6
0.00/0.89	, evenodd_2(2, 7) -> 6
0.00/0.89	, 0_0() -> 2
0.00/0.89	, 0_1() -> 5
0.00/0.89	, 0_2() -> 8
0.00/0.89	, s_0(2) -> 2
0.00/0.89	, s_1(5) -> 4
0.00/0.89	, s_2(8) -> 7 }
0.00/0.89	
0.00/0.89	Hurray, we answered YES(?,O(n^1))
0.00/0.89	EOF