MAYBE
0.09/0.18	MAYBE
0.09/0.18	
0.09/0.18	Problem:
0.09/0.18	 U11(tt(),V2) -> U12(isNat(activate(V2)))
0.09/0.18	 U12(tt()) -> tt()
0.09/0.18	 U21(tt()) -> tt()
0.09/0.18	 U31(tt(),N) -> activate(N)
0.09/0.18	 U41(tt(),M,N) -> U42(isNat(activate(N)),activate(M),activate(N))
0.09/0.18	 U42(tt(),M,N) -> s(plus(activate(N),activate(M)))
0.09/0.18	 isNat(n__0()) -> tt()
0.09/0.18	 isNat(n__plus(V1,V2)) -> U11(isNat(activate(V1)),activate(V2))
0.09/0.18	 isNat(n__s(V1)) -> U21(isNat(activate(V1)))
0.09/0.18	 plus(N,0()) -> U31(isNat(N),N)
0.09/0.18	 plus(N,s(M)) -> U41(isNat(M),M,N)
0.09/0.18	 0() -> n__0()
0.09/0.18	 plus(X1,X2) -> n__plus(X1,X2)
0.09/0.18	 s(X) -> n__s(X)
0.09/0.18	 activate(n__0()) -> 0()
0.09/0.18	 activate(n__plus(X1,X2)) -> plus(X1,X2)
0.09/0.18	 activate(n__s(X)) -> s(X)
0.09/0.18	 activate(X) -> X
0.09/0.18	
0.09/0.18	Proof:
0.09/0.18	 Open
0.09/0.18	EOF