NO
0.08/0.18	NO
0.08/0.18	
0.08/0.18	Problem:
0.08/0.18	 U12(tt()) -> s(length(L))
0.08/0.18	 zeros() -> cons(0())
0.08/0.18	 U11(tt()) -> U12(tt())
0.08/0.18	 length(nil()) -> 0()
0.08/0.18	 length(cons(N)) -> U11(tt())
0.08/0.18	
0.08/0.18	Proof:
0.08/0.18	 Fresh Variable Processor:
0.08/0.18	  loop length: 1
0.08/0.18	  terms:
0.08/0.18	   U12(tt())
0.08/0.18	  context: s(length([]))
0.08/0.18	  substitution:
0.08/0.18	   L -> U12(tt())
0.08/0.18	  Qed
0.08/0.18	EOF