MAYBE
0.08/0.18	MAYBE
0.08/0.18	
0.08/0.18	Problem:
0.08/0.18	 terms(N) -> cons(recip(sqr(N)),n__terms(n__s(N)))
0.08/0.18	 sqr(0()) -> 0()
0.08/0.18	 sqr(s(X)) -> s(add(sqr(X),dbl(X)))
0.08/0.18	 dbl(0()) -> 0()
0.08/0.18	 dbl(s(X)) -> s(s(dbl(X)))
0.08/0.18	 add(0(),X) -> X
0.08/0.18	 add(s(X),Y) -> s(add(X,Y))
0.08/0.18	 first(0(),X) -> nil()
0.08/0.18	 first(s(X),cons(Y,Z)) -> cons(Y,n__first(X,activate(Z)))
0.08/0.18	 half(0()) -> 0()
0.08/0.18	 half(s(0())) -> 0()
0.08/0.18	 half(s(s(X))) -> s(half(X))
0.08/0.18	 half(dbl(X)) -> X
0.08/0.18	 terms(X) -> n__terms(X)
0.08/0.18	 s(X) -> n__s(X)
0.08/0.18	 first(X1,X2) -> n__first(X1,X2)
0.08/0.18	 activate(n__terms(X)) -> terms(activate(X))
0.08/0.18	 activate(n__s(X)) -> s(activate(X))
0.08/0.18	 activate(n__first(X1,X2)) -> first(activate(X1),activate(X2))
0.08/0.18	 activate(X) -> X
0.08/0.18	
0.08/0.18	Proof:
0.08/0.18	 Open
0.08/0.19	EOF