NO
0.08/0.18	NO
0.08/0.18	
0.08/0.18	Problem:
0.08/0.18	 uTake2(tt()) -> cons(N)
0.08/0.18	 uLength(tt()) -> s(length(L))
0.08/0.18	 and(tt(),T) -> T
0.08/0.18	 isNatIList() -> isNatList()
0.08/0.18	 isNat() -> tt()
0.08/0.18	 isNat() -> isNat()
0.08/0.18	 isNat() -> isNatList()
0.08/0.18	 isNatIList() -> tt()
0.08/0.18	 isNatIList() -> and(isNat(),isNatIList())
0.08/0.18	 isNatList() -> tt()
0.08/0.18	 isNatList() -> and(isNat(),isNatList())
0.08/0.18	 isNatList() -> and(isNat(),isNatIList())
0.08/0.18	 zeros() -> cons(0())
0.08/0.18	 take(0(),IL) -> uTake1(isNatIList())
0.08/0.18	 uTake1(tt()) -> nil()
0.08/0.18	 take(s(M),cons(N)) -> uTake2(and(isNat(),and(isNat(),isNatIList())))
0.08/0.18	 length(cons(N)) -> uLength(and(isNat(),isNatList()))
0.08/0.18	
0.08/0.18	Proof:
0.08/0.18	 Fresh Variable Processor:
0.08/0.18	  loop length: 1
0.08/0.18	  terms:
0.08/0.18	   uTake2(tt())
0.08/0.18	  context: cons([])
0.08/0.18	  substitution:
0.08/0.18	   N -> uTake2(tt())
0.08/0.18	  Qed
0.08/0.19	EOF