NO
0.08/0.17	NO
0.08/0.17	
0.08/0.17	Problem:
0.08/0.17	 after(s(N),cons(X)) -> after(N,XS)
0.08/0.17	 from(X) -> cons(X)
0.08/0.17	 after(0(),XS) -> XS
0.08/0.17	
0.08/0.17	Proof:
0.08/0.17	 Fresh Variable Processor:
0.08/0.17	  loop length: 1
0.08/0.17	  terms:
0.08/0.17	   after(s(N),cons(X))
0.08/0.17	  context: after(N,[])
0.08/0.17	  substitution:
0.08/0.17	   XS -> after(s(N),cons(X))
0.08/0.17	  Qed
0.08/0.17	EOF