MAYBE
0.07/0.19	MAYBE
0.07/0.19	
0.07/0.19	Problem:
0.07/0.19	 a__dbl(0()) -> 0()
0.07/0.19	 a__dbl(s(X)) -> s(s(dbl(X)))
0.07/0.19	 a__dbls(nil()) -> nil()
0.07/0.19	 a__dbls(cons(X,Y)) -> cons(dbl(X),dbls(Y))
0.07/0.19	 a__sel(0(),cons(X,Y)) -> mark(X)
0.07/0.19	 a__sel(s(X),cons(Y,Z)) -> a__sel(mark(X),mark(Z))
0.07/0.19	 a__indx(nil(),X) -> nil()
0.07/0.19	 a__indx(cons(X,Y),Z) -> cons(sel(X,Z),indx(Y,Z))
0.07/0.19	 a__from(X) -> cons(X,from(s(X)))
0.07/0.19	 mark(dbl(X)) -> a__dbl(mark(X))
0.07/0.19	 mark(dbls(X)) -> a__dbls(mark(X))
0.07/0.19	 mark(sel(X1,X2)) -> a__sel(mark(X1),mark(X2))
0.07/0.19	 mark(indx(X1,X2)) -> a__indx(mark(X1),X2)
0.07/0.19	 mark(from(X)) -> a__from(X)
0.07/0.19	 mark(0()) -> 0()
0.07/0.19	 mark(s(X)) -> s(X)
0.07/0.19	 mark(nil()) -> nil()
0.07/0.19	 mark(cons(X1,X2)) -> cons(X1,X2)
0.07/0.19	 a__dbl(X) -> dbl(X)
0.07/0.19	 a__dbls(X) -> dbls(X)
0.07/0.19	 a__sel(X1,X2) -> sel(X1,X2)
0.07/0.19	 a__indx(X1,X2) -> indx(X1,X2)
0.07/0.19	 a__from(X) -> from(X)
0.07/0.19	
0.07/0.19	Proof:
0.07/0.19	 Open
0.07/0.19	EOF