NO
0.07/0.18	NO
0.07/0.18	
0.07/0.18	Problem:
0.07/0.18	 sel(s(X),cons(Y)) -> sel(X,Z)
0.07/0.18	 from(X) -> cons(X)
0.07/0.18	 first(0(),Z) -> nil()
0.07/0.18	 first(s(X),cons(Y)) -> cons(Y)
0.07/0.18	 sel(0(),cons(X)) -> X
0.07/0.18	
0.07/0.18	Proof:
0.07/0.18	 Fresh Variable Processor:
0.07/0.18	  loop length: 1
0.07/0.18	  terms:
0.07/0.18	   sel(s(X),cons(Y))
0.07/0.18	  context: sel(X,[])
0.07/0.18	  substitution:
0.07/0.18	   Z -> sel(s(X),cons(Y))
0.07/0.18	  Qed
0.07/0.18	EOF