MAYBE 0.08/0.18 MAYBE 0.08/0.18 0.08/0.18 Problem: 0.08/0.18 a__f(a(),b(),X) -> a__f(X,X,mark(X)) 0.08/0.18 a__c() -> a() 0.08/0.18 a__c() -> b() 0.08/0.18 mark(f(X1,X2,X3)) -> a__f(X1,X2,mark(X3)) 0.08/0.18 mark(c()) -> a__c() 0.08/0.18 mark(a()) -> a() 0.08/0.18 mark(b()) -> b() 0.08/0.18 a__f(X1,X2,X3) -> f(X1,X2,X3) 0.08/0.18 a__c() -> c() 0.08/0.18 0.08/0.18 Proof: 0.08/0.18 Open 0.08/0.18 EOF