NO 0.07/0.18 NO 0.07/0.18 0.07/0.18 Problem: 0.07/0.18 if(true()) -> X 0.07/0.18 if(false()) -> Y 0.07/0.18 p(0()) -> 0() 0.07/0.18 p(s(X)) -> X 0.07/0.18 leq(0(),Y) -> true() 0.07/0.18 leq(s(X),0()) -> false() 0.07/0.18 leq(s(X),s(Y)) -> leq(X,Y) 0.07/0.18 diff(X,Y) -> if(leq(X,Y)) 0.07/0.18 0.07/0.18 Proof: 0.07/0.18 Fresh Variable Processor: loop length: 1 0.07/0.18 terms: 0.07/0.18 if(true()) 0.07/0.18 context: [] 0.07/0.18 substitution: 0.07/0.18 X -> if(true()) 0.07/0.18 Qed 0.07/0.18 EOF