MAYBE
0.08/0.19	MAYBE
0.08/0.19	
0.08/0.19	Problem:
0.08/0.19	 a__p(0()) -> 0()
0.08/0.19	 a__p(s(X)) -> mark(X)
0.08/0.19	 a__leq(0(),Y) -> true()
0.08/0.19	 a__leq(s(X),0()) -> false()
0.08/0.19	 a__leq(s(X),s(Y)) -> a__leq(mark(X),mark(Y))
0.08/0.19	 a__if(true(),X,Y) -> mark(X)
0.08/0.19	 a__if(false(),X,Y) -> mark(Y)
0.08/0.19	 a__diff(X,Y) -> a__if(a__leq(mark(X),mark(Y)),0(),s(diff(p(X),Y)))
0.08/0.19	 mark(p(X)) -> a__p(mark(X))
0.08/0.19	 mark(leq(X1,X2)) -> a__leq(mark(X1),mark(X2))
0.08/0.19	 mark(if(X1,X2,X3)) -> a__if(mark(X1),X2,X3)
0.08/0.19	 mark(diff(X1,X2)) -> a__diff(mark(X1),mark(X2))
0.08/0.19	 mark(0()) -> 0()
0.08/0.19	 mark(s(X)) -> s(mark(X))
0.08/0.19	 mark(true()) -> true()
0.08/0.19	 mark(false()) -> false()
0.08/0.19	 a__p(X) -> p(X)
0.08/0.19	 a__leq(X1,X2) -> leq(X1,X2)
0.08/0.19	 a__if(X1,X2,X3) -> if(X1,X2,X3)
0.08/0.19	 a__diff(X1,X2) -> diff(X1,X2)
0.08/0.19	
0.08/0.19	Proof:
0.08/0.19	 Open
0.08/0.19	EOF