NO
0.08/0.17	NO
0.08/0.17	
0.08/0.17	Problem:
0.08/0.17	 2nd(cons(X)) -> Y
0.08/0.17	 from(X) -> cons(X)
0.08/0.17	
0.08/0.17	Proof:
0.08/0.17	 Fresh Variable Processor:
0.08/0.17	  loop length: 1
0.08/0.17	  terms:
0.08/0.17	   2nd(cons(X))
0.08/0.17	  context: []
0.08/0.17	  substitution:
0.08/0.17	   Y -> 2nd(cons(X))
0.08/0.17	  Qed
0.08/0.18	EOF