MAYBE
0.08/0.18	MAYBE
0.08/0.18	
0.08/0.18	Problem:
0.08/0.18	 f(s(x1),x2,x3,x4,x5) -> f(x1,x2,x3,x4,x5)
0.08/0.18	 f(0(),s(x2),x3,x4,x5) -> f(x2,x2,x3,x4,x5)
0.08/0.18	 f(0(),0(),s(x3),x4,x5) -> f(x3,x3,x3,x4,x5)
0.08/0.18	 f(0(),0(),0(),s(x4),x5) -> f(x4,x4,x4,x4,x5)
0.08/0.18	 f(0(),0(),0(),0(),s(x5)) -> f(x5,x5,x5,x5,x5)
0.08/0.18	 f(0(),0(),0(),0(),0()) -> 0()
0.08/0.18	
0.08/0.18	Proof:
0.08/0.18	 Open
0.08/0.18	EOF