MAYBE 0.08/0.18 MAYBE 0.08/0.18 0.08/0.18 Problem: 0.08/0.18 minus(X,0()) -> X 0.08/0.18 minus(s(X),s(Y)) -> p(minus(X,Y)) 0.08/0.18 p(s(X)) -> X 0.08/0.18 div(0(),s(Y)) -> 0() 0.08/0.18 div(s(X),s(Y)) -> s(div(minus(X,Y),s(Y))) 0.08/0.18 0.08/0.18 Proof: 0.08/0.18 Open 0.08/0.18 EOF