MAYBE
0.09/0.17	MAYBE
0.09/0.17	
0.09/0.17	Problem:
0.09/0.17	 nonZero(0()) -> false()
0.09/0.17	 nonZero(s(x)) -> true()
0.09/0.17	 p(0()) -> 0()
0.09/0.17	 p(s(x)) -> x
0.09/0.17	 id_inc(x) -> x
0.09/0.17	 id_inc(x) -> s(x)
0.09/0.17	 random(x) -> rand(x,0())
0.09/0.17	 rand(x,y) -> if(nonZero(x),x,y)
0.09/0.17	 if(false(),x,y) -> y
0.09/0.17	 if(true(),x,y) -> rand(p(x),id_inc(y))
0.09/0.17	
0.09/0.17	Proof:
0.09/0.17	 Open
0.09/0.17	EOF