MAYBE
0.08/0.18	MAYBE
0.08/0.18	
0.08/0.18	Problem:
0.08/0.18	 half(0()) -> 0()
0.08/0.18	 half(s(0())) -> 0()
0.08/0.18	 half(s(s(x))) -> s(half(x))
0.08/0.18	 inc(0()) -> 0()
0.08/0.18	 inc(s(x)) -> s(inc(x))
0.08/0.18	 zero(0()) -> true()
0.08/0.18	 zero(s(x)) -> false()
0.08/0.18	 p(0()) -> 0()
0.08/0.18	 p(s(x)) -> x
0.08/0.18	 bits(x) -> bitIter(x,0())
0.08/0.18	 bitIter(x,y) -> if(zero(x),x,inc(y))
0.08/0.18	 if(true(),x,y) -> p(y)
0.08/0.18	 if(false(),x,y) -> bitIter(half(x),y)
0.08/0.18	
0.08/0.18	Proof:
0.08/0.18	 Open
0.08/0.18	EOF