MAYBE
0.07/0.18	MAYBE
0.07/0.18	
0.07/0.18	Problem:
0.07/0.18	 h(c(x,y),c(s(z),z),t(w)) -> h(z,c(y,x),t(t(c(x,c(y,t(w))))))
0.07/0.18	 h(x,c(y,z),t(w)) -> h(c(s(y),x),z,t(c(t(w),w)))
0.07/0.18	 h(c(s(x),c(s(0()),y)),z,t(x)) -> h(y,c(s(0()),c(x,z)),t(t(c(x,s(x)))))
0.07/0.18	 t(t(x)) -> t(c(t(x),x))
0.07/0.18	 t(x) -> x
0.07/0.18	 t(x) -> c(0(),c(0(),c(0(),c(0(),c(0(),x)))))
0.07/0.18	
0.07/0.18	Proof:
0.07/0.18	 Open
0.07/0.19	EOF