MAYBE
0.07/0.18	MAYBE
0.07/0.19	
0.07/0.19	Problem:
0.07/0.19	 plus(s(s(x)),y) -> s(plus(x,s(y)))
0.07/0.19	 plus(x,s(s(y))) -> s(plus(s(x),y))
0.07/0.19	 plus(s(0()),y) -> s(y)
0.07/0.19	 plus(0(),y) -> y
0.07/0.19	 ack(0(),y) -> s(y)
0.07/0.19	 ack(s(x),0()) -> ack(x,s(0()))
0.07/0.19	 ack(s(x),s(y)) -> ack(x,plus(y,ack(s(x),y)))
0.07/0.19	
0.07/0.19	Proof:
0.07/0.19	 Open
0.07/0.19	EOF