YES(?,O(n^1))
0.16/0.23	YES(?,O(n^1))
0.16/0.23	
0.16/0.23	Problem:
0.16/0.23	 g(c(x,s(y))) -> g(c(s(x),y))
0.16/0.23	 f(c(s(x),y)) -> f(c(x,s(y)))
0.16/0.23	 f(f(x)) -> f(d(f(x)))
0.16/0.23	 f(x) -> x
0.16/0.23	
0.16/0.23	Proof:
0.16/0.23	 Bounds Processor:
0.16/0.23	  bound: 1
0.16/0.23	  enrichment: match
0.16/0.23	  automaton:
0.16/0.23	   final states: {5,4}
0.16/0.23	   transitions:
0.16/0.23	    f1(11) -> 5*
0.16/0.23	    c1(6,2) -> 7*
0.16/0.23	    c1(1,6) -> 11*
0.16/0.23	    c1(3,6) -> 11*
0.16/0.23	    c1(6,1) -> 7*
0.16/0.23	    c1(6,3) -> 7*
0.16/0.23	    c1(2,6) -> 11*
0.16/0.23	    s1(2) -> 6*
0.16/0.23	    s1(6) -> 6*
0.16/0.23	    s1(1) -> 6*
0.16/0.23	    s1(3) -> 6*
0.16/0.23	    g1(7) -> 4*
0.16/0.23	    g0(2) -> 4*
0.16/0.23	    g0(1) -> 4*
0.16/0.23	    g0(3) -> 4*
0.16/0.23	    c0(3,1) -> 1*
0.16/0.23	    c0(3,3) -> 1*
0.16/0.23	    c0(1,2) -> 1*
0.16/0.23	    c0(2,1) -> 1*
0.16/0.23	    c0(2,3) -> 1*
0.16/0.23	    c0(3,2) -> 1*
0.16/0.23	    c0(1,1) -> 1*
0.16/0.23	    c0(1,3) -> 1*
0.16/0.23	    c0(2,2) -> 1*
0.16/0.23	    s0(2) -> 2*
0.16/0.23	    s0(1) -> 2*
0.16/0.23	    s0(3) -> 2*
0.16/0.23	    f0(2) -> 5*
0.16/0.23	    f0(1) -> 5*
0.16/0.23	    f0(3) -> 5*
0.16/0.23	    d0(2) -> 3*
0.16/0.23	    d0(1) -> 3*
0.16/0.23	    d0(3) -> 3*
0.16/0.23	    1 -> 5*
0.16/0.23	    2 -> 5*
0.16/0.23	    3 -> 5*
0.16/0.23	    11 -> 5*
0.16/0.23	  problem:
0.16/0.23	   
0.16/0.23	  Qed
0.16/0.23	EOF