MAYBE
0.09/0.17	MAYBE
0.09/0.17	
0.09/0.17	Problem:
0.09/0.17	 minus(x,0()) -> x
0.09/0.17	 minus(s(x),s(y)) -> minus(x,y)
0.09/0.17	 quot(0(),s(y)) -> 0()
0.09/0.17	 quot(s(x),s(y)) -> s(quot(minus(x,y),s(y)))
0.09/0.17	
0.09/0.17	Proof:
0.09/0.17	 Open
0.09/0.17	EOF