YES(O(1),O(n^2)) 163.05/60.06 YES(O(1),O(n^2)) 163.05/60.06 163.05/60.06 We are left with following problem, upon which TcT provides the 163.05/60.06 certificate YES(O(1),O(n^2)). 163.05/60.06 163.05/60.06 Strict Trs: 163.05/60.06 { +(-(x, y), z) -> -(+(x, z), y) 163.05/60.06 , -(+(x, y), y) -> x } 163.05/60.06 Obligation: 163.05/60.06 derivational complexity 163.05/60.06 Answer: 163.05/60.06 YES(O(1),O(n^2)) 163.05/60.06 163.05/60.06 We use the processor 'matrix interpretation of dimension 1' to 163.05/60.06 orient following rules strictly. 163.05/60.06 163.05/60.06 Trs: { -(+(x, y), y) -> x } 163.05/60.06 163.05/60.06 The induced complexity on above rules (modulo remaining rules) is 163.05/60.06 YES(?,O(n^1)) . These rules are moved into the corresponding weak 163.05/60.06 component(s). 163.05/60.06 163.05/60.06 Sub-proof: 163.05/60.06 ---------- 163.05/60.06 TcT has computed the following triangular matrix interpretation. 163.05/60.06 163.05/60.06 [+](x1, x2) = [1] x1 + [1] x2 + [1] 163.05/60.06 163.05/60.06 [-](x1, x2) = [1] x1 + [1] x2 + [0] 163.05/60.06 163.05/60.06 The order satisfies the following ordering constraints: 163.05/60.06 163.05/60.06 [+(-(x, y), z)] = [1] x + [1] y + [1] z + [1] 163.05/60.06 >= [1] x + [1] y + [1] z + [1] 163.05/60.06 = [-(+(x, z), y)] 163.05/60.06 163.05/60.06 [-(+(x, y), y)] = [1] x + [2] y + [1] 163.05/60.06 > [1] x + [0] 163.05/60.06 = [x] 163.05/60.06 163.05/60.06 163.05/60.06 We return to the main proof. 163.05/60.06 163.05/60.06 We are left with following problem, upon which TcT provides the 163.05/60.06 certificate YES(O(1),O(n^2)). 163.05/60.06 163.05/60.06 Strict Trs: { +(-(x, y), z) -> -(+(x, z), y) } 163.05/60.06 Weak Trs: { -(+(x, y), y) -> x } 163.05/60.06 Obligation: 163.05/60.06 derivational complexity 163.05/60.06 Answer: 163.05/60.06 YES(O(1),O(n^2)) 163.05/60.06 163.05/60.06 We use the processor 'matrix interpretation of dimension 2' to 163.05/60.06 orient following rules strictly. 163.05/60.06 163.05/60.06 Trs: { +(-(x, y), z) -> -(+(x, z), y) } 163.05/60.06 163.05/60.06 The induced complexity on above rules (modulo remaining rules) is 163.05/60.06 YES(?,O(n^2)) . These rules are moved into the corresponding weak 163.05/60.06 component(s). 163.05/60.06 163.05/60.06 Sub-proof: 163.05/60.06 ---------- 163.05/60.06 TcT has computed the following triangular matrix interpretation. 163.05/60.06 163.05/60.06 [+](x1, x2) = [1 1] x1 + [1 2] x2 + [0] 163.05/60.06 [0 1] [0 1] [2] 163.05/60.06 163.05/60.06 [-](x1, x2) = [1 0] x1 + [1 1] x2 + [0] 163.05/60.06 [0 1] [0 1] [1] 163.05/60.06 163.05/60.06 The order satisfies the following ordering constraints: 163.05/60.06 163.05/60.06 [+(-(x, y), z)] = [1 1] x + [1 2] y + [1 2] z + [1] 163.05/60.06 [0 1] [0 1] [0 1] [3] 163.05/60.06 > [1 1] x + [1 1] y + [1 2] z + [0] 163.05/60.06 [0 1] [0 1] [0 1] [3] 163.05/60.06 = [-(+(x, z), y)] 163.05/60.06 163.05/60.06 [-(+(x, y), y)] = [1 1] x + [2 3] y + [0] 163.05/60.06 [0 1] [0 2] [3] 163.05/60.06 >= [1 0] x + [0] 163.05/60.06 [0 1] [0] 163.05/60.06 = [x] 163.05/60.06 163.05/60.06 163.05/60.06 We return to the main proof. 163.05/60.06 163.05/60.06 We are left with following problem, upon which TcT provides the 163.05/60.06 certificate YES(O(1),O(1)). 163.05/60.06 163.05/60.06 Weak Trs: 163.05/60.06 { +(-(x, y), z) -> -(+(x, z), y) 163.05/60.06 , -(+(x, y), y) -> x } 163.05/60.06 Obligation: 163.05/60.06 derivational complexity 163.05/60.06 Answer: 163.05/60.06 YES(O(1),O(1)) 163.05/60.06 163.05/60.06 Empty rules are trivially bounded 163.05/60.06 163.05/60.06 Hurray, we answered YES(O(1),O(n^2)) 163.05/60.08 EOF