MAYBE 1149.31/297.08 MAYBE 1149.31/297.08 1149.31/297.08 We are left with following problem, upon which TcT provides the 1149.31/297.08 certificate MAYBE. 1149.31/297.08 1149.31/297.08 Strict Trs: 1149.31/297.08 { 0(0(1(x1))) -> 0(0(2(1(3(x1))))) 1149.31/297.08 , 0(0(1(x1))) -> 0(0(2(2(3(1(x1)))))) 1149.31/297.08 , 0(0(3(3(1(x1))))) -> 0(3(0(1(2(3(x1)))))) 1149.31/297.08 , 0(0(4(5(x1)))) -> 0(5(0(2(4(2(x1)))))) 1149.31/297.08 , 0(1(2(0(x1)))) -> 2(0(2(1(0(x1))))) 1149.31/297.08 , 0(2(0(1(x1)))) -> 0(0(2(1(3(x1))))) 1149.31/297.08 , 0(2(4(3(1(x1))))) -> 0(2(3(1(4(2(x1)))))) 1149.31/297.08 , 0(3(4(0(x1)))) -> 3(2(4(0(0(3(x1)))))) 1149.31/297.08 , 0(4(0(4(x1)))) -> 0(0(3(2(4(4(x1)))))) 1149.31/297.08 , 0(4(1(x1))) -> 0(2(3(1(4(2(x1)))))) 1149.31/297.08 , 0(4(1(x1))) -> 0(4(2(2(1(x1))))) 1149.31/297.08 , 0(5(4(1(1(x1))))) -> 4(0(2(5(1(1(x1)))))) 1149.31/297.08 , 1(0(1(x1))) -> 0(2(1(1(x1)))) 1149.31/297.08 , 1(0(1(x1))) -> 0(2(1(1(2(x1))))) 1149.31/297.08 , 1(0(1(x1))) -> 1(0(3(2(1(x1))))) 1149.31/297.08 , 1(0(1(4(x1)))) -> 2(3(1(1(4(0(x1)))))) 1149.31/297.08 , 1(0(3(1(x1)))) -> 4(2(3(1(1(0(x1)))))) 1149.31/297.08 , 1(2(0(4(x1)))) -> 1(4(2(0(3(2(x1)))))) 1149.31/297.08 , 1(2(4(3(1(x1))))) -> 1(2(3(3(1(4(x1)))))) 1149.31/297.08 , 1(3(0(4(x1)))) -> 4(0(3(2(1(3(x1)))))) 1149.31/297.08 , 1(4(0(x1))) -> 1(0(3(2(4(2(x1)))))) 1149.31/297.08 , 1(4(1(x1))) -> 4(2(1(1(x1)))) 1149.31/297.08 , 1(4(1(x1))) -> 4(2(1(1(2(1(x1)))))) 1149.31/297.08 , 1(4(1(5(x1)))) -> 2(1(2(5(1(4(x1)))))) 1149.31/297.08 , 4(0(0(3(1(x1))))) -> 4(0(3(2(1(0(x1)))))) 1149.31/297.08 , 4(0(0(3(1(x1))))) -> 4(3(2(0(0(1(x1)))))) 1149.31/297.08 , 4(0(1(x1))) -> 4(0(2(1(x1)))) 1149.31/297.08 , 4(0(5(1(x1)))) -> 0(2(4(2(1(5(x1)))))) 1149.31/297.08 , 4(1(0(0(x1)))) -> 3(2(1(4(0(0(x1)))))) 1149.31/297.08 , 4(1(0(4(x1)))) -> 4(4(0(2(1(x1))))) 1149.31/297.08 , 5(0(0(1(x1)))) -> 0(3(2(5(1(0(x1)))))) 1149.31/297.08 , 5(0(1(x1))) -> 0(2(1(5(3(x1))))) 1149.31/297.08 , 5(0(1(x1))) -> 0(3(2(1(5(5(x1)))))) 1149.31/297.08 , 5(0(1(x1))) -> 3(0(2(3(5(1(x1)))))) 1149.31/297.08 , 5(0(1(x1))) -> 5(0(2(1(x1)))) 1149.31/297.08 , 5(0(3(1(x1)))) -> 0(3(5(2(2(1(x1)))))) 1149.31/297.08 , 5(0(3(1(x1)))) -> 0(5(3(2(1(x1))))) 1149.31/297.08 , 5(0(5(x1))) -> 0(3(2(5(3(5(x1)))))) 1149.31/297.08 , 5(0(5(1(x1)))) -> 5(2(5(3(1(0(x1)))))) 1149.31/297.08 , 5(1(0(0(5(x1))))) -> 5(0(0(2(1(5(x1)))))) 1149.31/297.08 , 5(2(4(1(x1)))) -> 2(1(4(2(5(x1))))) 1149.31/297.08 , 5(4(1(x1))) -> 2(4(2(5(1(3(x1)))))) 1149.31/297.08 , 5(4(1(x1))) -> 4(5(2(1(3(3(x1)))))) 1149.31/297.08 , 5(4(1(5(x1)))) -> 2(1(5(4(2(5(x1)))))) 1149.31/297.08 , 5(4(1(5(x1)))) -> 4(5(5(2(1(x1))))) 1149.31/297.08 , 5(4(2(0(1(x1))))) -> 2(5(4(0(2(1(x1)))))) 1149.31/297.08 , 5(4(3(1(x1)))) -> 3(5(2(4(2(1(x1)))))) 1149.31/297.08 , 5(4(3(1(x1)))) -> 5(2(4(3(2(1(x1)))))) 1149.31/297.08 , 5(4(3(1(x1)))) -> 5(4(2(1(3(x1))))) 1149.31/297.08 , 5(5(0(4(x1)))) -> 5(0(2(5(4(2(x1)))))) } 1149.31/297.08 Obligation: 1149.31/297.08 derivational complexity 1149.31/297.08 Answer: 1149.31/297.08 MAYBE 1149.31/297.08 1149.31/297.08 None of the processors succeeded. 1149.31/297.08 1149.31/297.08 Details of failed attempt(s): 1149.31/297.08 ----------------------------- 1149.31/297.08 1) 'bsearch-matrix (timeout of 297 seconds)' failed due to the 1149.31/297.08 following reason: 1149.31/297.08 1149.31/297.08 Computation stopped due to timeout after 297.0 seconds. 1149.31/297.08 1149.31/297.08 2) 'Inspecting Problem... (timeout of 297 seconds)' failed due to 1149.31/297.08 the following reason: 1149.31/297.08 1149.31/297.08 Computation stopped due to timeout after 297.0 seconds. 1149.31/297.08 1149.31/297.08 3) 'iteProgress (timeout of 297 seconds)' failed due to the 1149.31/297.08 following reason: 1149.31/297.08 1149.31/297.08 Computation stopped due to timeout after 297.0 seconds. 1149.31/297.08 1149.31/297.08 4) 'Fastest (timeout of 60 seconds)' failed due to the following 1149.31/297.08 reason: 1149.31/297.08 1149.31/297.08 Computation stopped due to timeout after 60.0 seconds. 1149.31/297.08 1149.31/297.08 1149.31/297.08 Arrrr.. 1149.83/297.37 EOF