MAYBE 1163.14/297.07 MAYBE 1163.14/297.07 1163.14/297.07 We are left with following problem, upon which TcT provides the 1163.14/297.07 certificate MAYBE. 1163.14/297.07 1163.14/297.07 Strict Trs: 1163.14/297.07 { 0(0(2(1(0(x1))))) -> 2(0(0(0(3(1(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 0(1(2(2(0(x1))))) 1163.14/297.07 , 0(1(0(x1))) -> 0(1(2(4(0(3(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 1(2(2(0(0(4(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 1(2(3(4(0(0(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 1(3(2(0(0(0(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 1(3(4(0(2(0(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 1(3(4(4(0(0(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(0(1(x1)))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(0(1(2(2(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(0(2(0(1(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(0(3(0(1(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(0(3(1(x1))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(0(2(0(4(1(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(1(2(2(0(0(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 2(4(0(4(0(1(x1)))))) 1163.14/297.07 , 0(1(0(x1))) -> 4(1(2(2(0(0(x1)))))) 1163.14/297.07 , 0(1(1(0(x1)))) -> 2(2(0(0(1(1(x1)))))) 1163.14/297.07 , 0(1(2(0(1(x1))))) -> 0(0(1(3(2(1(x1)))))) 1163.14/297.07 , 0(1(2(0(1(x1))))) -> 0(2(0(3(1(1(x1)))))) 1163.14/297.07 , 0(1(5(0(x1)))) -> 0(3(3(5(1(0(x1)))))) 1163.14/297.07 , 0(1(5(0(x1)))) -> 0(3(5(1(0(x1))))) 1163.14/297.07 , 0(5(5(0(x1)))) -> 2(2(0(0(5(5(x1)))))) 1163.14/297.07 , 1(0(1(0(x1)))) -> 1(1(3(5(0(0(x1)))))) 1163.14/297.07 , 1(3(0(1(x1)))) -> 1(1(0(3(4(1(x1)))))) 1163.14/297.07 , 1(3(0(1(x1)))) -> 5(1(1(3(4(0(x1)))))) 1163.14/297.07 , 1(3(0(2(1(x1))))) -> 0(2(1(1(3(2(x1)))))) 1163.14/297.07 , 1(3(0(2(1(x1))))) -> 0(3(2(2(1(1(x1)))))) 1163.14/297.07 , 1(3(0(5(5(x1))))) -> 0(5(4(3(5(1(x1)))))) 1163.14/297.07 , 1(3(1(5(0(x1))))) -> 1(3(1(5(2(0(x1)))))) 1163.14/297.07 , 3(0(1(0(x1)))) -> 0(1(3(2(0(4(x1)))))) 1163.14/297.07 , 3(0(1(0(x1)))) -> 2(0(4(3(0(1(x1)))))) 1163.14/297.07 , 3(0(1(0(x1)))) -> 2(2(3(0(0(1(x1)))))) 1163.14/297.07 , 3(0(1(0(x1)))) -> 3(0(2(2(0(1(x1)))))) 1163.14/297.07 , 3(0(5(0(0(x1))))) -> 3(0(0(3(5(0(x1)))))) 1163.14/297.07 , 3(0(5(5(0(x1))))) -> 5(0(2(3(5(0(x1)))))) 1163.14/297.07 , 3(1(0(0(x1)))) -> 1(0(3(4(0(x1))))) 1163.14/297.07 , 3(1(0(0(x1)))) -> 1(2(0(3(0(2(x1)))))) 1163.14/297.07 , 3(1(0(0(x1)))) -> 2(0(3(1(0(x1))))) 1163.14/297.07 , 3(1(0(0(x1)))) -> 3(0(0(5(1(x1))))) 1163.14/297.07 , 3(1(0(0(x1)))) -> 3(1(3(0(2(0(x1)))))) 1163.14/297.07 , 3(1(4(0(0(x1))))) -> 1(0(0(3(4(0(x1)))))) 1163.14/297.07 , 3(1(4(5(0(x1))))) -> 0(5(1(3(5(4(x1)))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 0(2(5(1(3(5(x1)))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 0(3(1(3(4(5(x1)))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 1(1(3(5(0(x1))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 1(5(2(3(5(0(x1)))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 3(1(4(0(2(5(x1)))))) 1163.14/297.07 , 3(1(5(0(x1)))) -> 4(0(5(1(3(5(x1)))))) } 1163.14/297.07 Obligation: 1163.14/297.07 derivational complexity 1163.14/297.07 Answer: 1163.14/297.07 MAYBE 1163.14/297.07 1163.14/297.07 None of the processors succeeded. 1163.14/297.07 1163.14/297.07 Details of failed attempt(s): 1163.14/297.07 ----------------------------- 1163.14/297.07 1) 'Inspecting Problem... (timeout of 297 seconds)' failed due to 1163.14/297.07 the following reason: 1163.14/297.07 1163.14/297.07 Computation stopped due to timeout after 297.0 seconds. 1163.14/297.07 1163.14/297.07 2) 'iteProgress (timeout of 297 seconds)' failed due to the 1163.14/297.07 following reason: 1163.14/297.07 1163.14/297.07 Computation stopped due to timeout after 297.0 seconds. 1163.14/297.07 1163.14/297.07 3) 'bsearch-matrix (timeout of 297 seconds)' failed due to the 1163.14/297.07 following reason: 1163.14/297.07 1163.14/297.07 Computation stopped due to timeout after 297.0 seconds. 1163.14/297.07 1163.14/297.07 4) 'Fastest (timeout of 60 seconds)' failed due to the following 1163.14/297.07 reason: 1163.14/297.07 1163.14/297.07 Computation stopped due to timeout after 60.0 seconds. 1163.14/297.07 1163.14/297.07 1163.14/297.07 Arrrr.. 1163.82/297.54 EOF