MAYBE 1144.35/297.05 MAYBE 1144.35/297.05 1144.35/297.05 We are left with following problem, upon which TcT provides the 1144.35/297.05 certificate MAYBE. 1144.35/297.05 1144.35/297.05 Strict Trs: 1144.35/297.05 { 0(1(1(2(x1)))) -> 0(2(1(1(3(x1))))) 1144.35/297.05 , 0(1(2(x1))) -> 0(2(1(1(x1)))) 1144.35/297.05 , 0(1(2(x1))) -> 0(2(1(1(3(x1))))) 1144.35/297.05 , 0(1(2(x1))) -> 0(2(1(3(x1)))) 1144.35/297.05 , 0(1(2(x1))) -> 0(2(4(1(1(x1))))) 1144.35/297.05 , 0(1(2(x1))) -> 0(2(4(1(3(x1))))) 1144.35/297.05 , 0(1(2(2(x1)))) -> 0(2(2(1(1(x1))))) 1144.35/297.05 , 0(1(2(2(x1)))) -> 0(2(3(2(1(x1))))) 1144.35/297.05 , 0(1(2(4(2(x1))))) -> 4(2(1(0(2(1(x1)))))) 1144.35/297.05 , 0(1(2(5(2(x1))))) -> 2(0(2(1(5(4(x1)))))) 1144.35/297.05 , 0(1(3(2(x1)))) -> 0(2(1(4(3(x1))))) 1144.35/297.05 , 0(1(3(2(x1)))) -> 3(0(2(4(1(1(x1)))))) 1144.35/297.05 , 0(1(3(2(x1)))) -> 3(3(0(2(1(x1))))) 1144.35/297.05 , 0(1(5(1(2(x1))))) -> 1(0(2(1(1(5(x1)))))) 1144.35/297.05 , 0(1(5(2(x1)))) -> 5(0(2(1(1(x1))))) 1144.35/297.05 , 0(1(5(5(2(x1))))) -> 0(2(1(5(5(1(x1)))))) 1144.35/297.05 , 0(3(2(x1))) -> 0(0(2(1(1(3(x1)))))) 1144.35/297.05 , 0(3(2(x1))) -> 0(2(1(1(3(x1))))) 1144.35/297.05 , 0(3(2(x1))) -> 0(2(1(3(x1)))) 1144.35/297.05 , 0(3(2(2(x1)))) -> 0(0(2(3(2(x1))))) 1144.35/297.05 , 0(3(2(2(x1)))) -> 0(0(4(2(3(2(x1)))))) 1144.35/297.05 , 0(5(0(1(2(x1))))) -> 0(4(5(0(2(1(x1)))))) 1144.35/297.05 , 0(5(0(3(2(x1))))) -> 0(5(0(0(2(3(x1)))))) 1144.35/297.05 , 0(5(5(2(2(x1))))) -> 0(2(1(5(5(2(x1)))))) 1144.35/297.05 , 2(0(3(2(x1)))) -> 1(3(0(2(2(x1))))) 1144.35/297.05 , 3(0(3(1(2(x1))))) -> 1(3(3(0(2(3(x1)))))) 1144.35/297.05 , 3(0(3(2(x1)))) -> 3(0(0(0(2(3(x1)))))) 1144.35/297.05 , 3(0(3(4(2(x1))))) -> 1(3(4(0(2(3(x1)))))) 1144.35/297.05 , 3(1(5(2(x1)))) -> 0(2(1(5(3(x1))))) 1144.35/297.05 , 3(3(5(2(x1)))) -> 3(0(2(1(5(3(x1)))))) 1144.35/297.05 , 4(5(1(4(2(x1))))) -> 2(4(4(4(1(5(x1)))))) 1144.35/297.05 , 4(5(2(2(x1)))) -> 2(5(0(2(4(1(x1)))))) 1144.35/297.05 , 5(0(1(2(x1)))) -> 0(2(1(3(4(5(x1)))))) 1144.35/297.05 , 5(0(1(3(2(x1))))) -> 3(5(0(2(1(3(x1)))))) 1144.35/297.05 , 5(0(2(2(x1)))) -> 2(0(2(4(1(5(x1)))))) 1144.35/297.05 , 5(0(3(1(2(x1))))) -> 0(2(1(4(3(5(x1)))))) 1144.35/297.05 , 5(0(3(2(x1)))) -> 3(0(2(1(4(5(x1)))))) 1144.35/297.05 , 5(0(4(2(2(x1))))) -> 2(0(2(4(1(5(x1)))))) 1144.35/297.05 , 5(1(0(3(2(x1))))) -> 0(4(3(5(1(2(x1)))))) 1144.35/297.05 , 5(1(0(3(2(x1))))) -> 5(3(1(1(0(2(x1)))))) 1144.35/297.05 , 5(1(0(5(2(x1))))) -> 3(5(5(0(2(1(x1)))))) 1144.35/297.05 , 5(1(0(5(2(x1))))) -> 5(0(2(1(5(5(x1)))))) 1144.35/297.05 , 5(1(2(2(x1)))) -> 0(2(1(5(2(1(x1)))))) 1144.35/297.05 , 5(1(2(2(x1)))) -> 2(1(5(2(1(1(x1)))))) 1144.35/297.05 , 5(2(0(3(2(x1))))) -> 0(2(5(2(3(1(x1)))))) } 1144.35/297.05 Obligation: 1144.35/297.05 derivational complexity 1144.35/297.05 Answer: 1144.35/297.05 MAYBE 1144.35/297.05 1144.35/297.05 None of the processors succeeded. 1144.35/297.05 1144.35/297.05 Details of failed attempt(s): 1144.35/297.05 ----------------------------- 1144.35/297.05 1) 'bsearch-matrix (timeout of 297 seconds)' failed due to the 1144.35/297.05 following reason: 1144.35/297.05 1144.35/297.05 Computation stopped due to timeout after 297.0 seconds. 1144.35/297.05 1144.35/297.05 2) 'Inspecting Problem... (timeout of 297 seconds)' failed due to 1144.35/297.05 the following reason: 1144.35/297.05 1144.35/297.05 Computation stopped due to timeout after 297.0 seconds. 1144.35/297.05 1144.35/297.05 3) 'iteProgress (timeout of 297 seconds)' failed due to the 1144.35/297.05 following reason: 1144.35/297.05 1144.35/297.05 Fail 1144.35/297.05 1144.35/297.05 4) 'Fastest (timeout of 60 seconds)' failed due to the following 1144.35/297.05 reason: 1144.35/297.05 1144.35/297.05 Computation stopped due to timeout after 60.0 seconds. 1144.35/297.05 1144.35/297.05 1144.35/297.05 Arrrr.. 1144.62/297.28 EOF