YES(?,O(n^1)) 8.56/5.09 YES(?,O(n^1)) 8.56/5.09 8.56/5.09 We are left with following problem, upon which TcT provides the 8.56/5.09 certificate YES(?,O(n^1)). 8.56/5.09 8.56/5.09 Strict Trs: 8.56/5.09 { \(x, x) -> e() 8.56/5.09 , \(x, .(x, y)) -> y 8.56/5.09 , \(e(), x) -> x 8.56/5.09 , \(/(x, y), x) -> y 8.56/5.09 , /(x, x) -> e() 8.56/5.09 , /(x, \(y, x)) -> y 8.56/5.09 , /(x, e()) -> x 8.56/5.09 , /(.(y, x), x) -> y 8.56/5.09 , .(x, \(x, y)) -> y 8.56/5.09 , .(x, e()) -> x 8.56/5.09 , .(e(), x) -> x 8.56/5.09 , .(/(y, x), x) -> y } 8.56/5.09 Obligation: 8.56/5.09 derivational complexity 8.56/5.09 Answer: 8.56/5.09 YES(?,O(n^1)) 8.56/5.09 8.56/5.09 TcT has computed the following matrix interpretation satisfying 8.56/5.09 not(EDA) and not(IDA(1)). 8.56/5.09 8.56/5.09 [1 0 0 0] [1 0 0 0] [1] 8.56/5.09 [\](x1, x2) = [0 1 0 0] x1 + [0 1 0 0] x2 + [1] 8.56/5.09 [0 0 1 0] [0 0 1 0] [0] 8.56/5.09 [0 0 1 1] [0 0 1 1] [0] 8.56/5.09 8.56/5.09 [0] 8.56/5.09 [e] = [0] 8.56/5.09 [0] 8.56/5.09 [0] 8.56/5.09 8.56/5.09 [1 0 0 0] [1 0 0 0] [1] 8.56/5.09 [/](x1, x2) = [0 1 0 0] x1 + [0 1 0 0] x2 + [1] 8.56/5.09 [0 0 1 0] [0 0 1 1] [0] 8.56/5.09 [0 0 1 1] [0 0 0 1] [0] 8.56/5.09 8.56/5.09 [1 0 0 0] [1 0 0 0] [1] 8.56/5.09 [.](x1, x2) = [0 1 0 0] x1 + [0 1 0 0] x2 + [0] 8.56/5.09 [0 0 1 1] [0 0 1 1] [0] 8.56/5.09 [0 0 0 1] [0 0 0 1] [0] 8.56/5.09 8.56/5.09 The order satisfies the following ordering constraints: 8.56/5.09 8.56/5.09 [\(x, x)] = [2 0 0 0] [1] 8.56/5.09 [0 2 0 0] x + [1] 8.56/5.09 [0 0 2 0] [0] 8.56/5.09 [0 0 2 2] [0] 8.56/5.09 > [0] 8.56/5.09 [0] 8.56/5.09 [0] 8.56/5.09 [0] 8.56/5.09 = [e()] 8.56/5.09 8.56/5.09 [\(x, .(x, y))] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [1] 8.56/5.09 [0 0 2 1] [0 0 1 1] [0] 8.56/5.09 [0 0 2 3] [0 0 1 2] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 [\(e(), x)] = [1 0 0 0] [1] 8.56/5.09 [0 1 0 0] x + [1] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 1 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [x] 8.56/5.09 8.56/5.09 [\(/(x, y), x)] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [2] 8.56/5.09 [0 0 2 0] [0 0 1 1] [0] 8.56/5.09 [0 0 3 2] [0 0 1 2] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 [/(x, x)] = [2 0 0 0] [1] 8.56/5.09 [0 2 0 0] x + [1] 8.56/5.09 [0 0 2 1] [0] 8.56/5.09 [0 0 1 2] [0] 8.56/5.09 > [0] 8.56/5.09 [0] 8.56/5.09 [0] 8.56/5.09 [0] 8.56/5.09 = [e()] 8.56/5.09 8.56/5.09 [/(x, \(y, x))] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [2] 8.56/5.09 [0 0 3 1] [0 0 2 1] [0] 8.56/5.09 [0 0 2 2] [0 0 1 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 [/(x, e())] = [1 0 0 0] [1] 8.56/5.09 [0 1 0 0] x + [1] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 1 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [x] 8.56/5.09 8.56/5.09 [/(.(y, x), x)] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [1] 8.56/5.09 [0 0 2 2] [0 0 1 1] [0] 8.56/5.09 [0 0 1 3] [0 0 1 2] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 [.(x, \(x, y))] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [1] 8.56/5.09 [0 0 3 2] [0 0 2 1] [0] 8.56/5.09 [0 0 1 2] [0 0 1 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 [.(x, e())] = [1 0 0 0] [1] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 1] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [x] 8.56/5.09 8.56/5.09 [.(e(), x)] = [1 0 0 0] [1] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 1] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] x + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [x] 8.56/5.09 8.56/5.09 [.(/(y, x), x)] = [2 0 0 0] [1 0 0 0] [2] 8.56/5.09 [0 2 0 0] x + [0 1 0 0] y + [1] 8.56/5.09 [0 0 2 3] [0 0 2 1] [0] 8.56/5.09 [0 0 0 2] [0 0 1 1] [0] 8.56/5.09 > [1 0 0 0] [0] 8.56/5.09 [0 1 0 0] y + [0] 8.56/5.09 [0 0 1 0] [0] 8.56/5.09 [0 0 0 1] [0] 8.56/5.09 = [y] 8.56/5.09 8.56/5.09 8.56/5.09 Hurray, we answered YES(?,O(n^1)) 8.71/5.11 EOF