MAYBE
100.20/55.37	MAYBE
100.20/55.37	
100.20/55.37	Problem:
100.20/55.37	 a(x1) -> b(c(x1))
100.20/55.37	 b(b(x1)) -> x1
100.20/55.37	 c(c(b(x1))) -> b(c(a(c(x1))))
100.20/55.37	
100.20/55.37	Proof:
100.20/55.37	 Open
100.20/55.37	EOF