NO
0.08/0.17	NO
0.08/0.17	
0.08/0.17	Problem:
0.08/0.17	 and(tt()) -> X
0.08/0.17	 length(cons(N)) -> s(length(L))
0.08/0.17	 zeros() -> cons(0())
0.08/0.17	 length(nil()) -> 0()
0.08/0.17	
0.08/0.17	Proof:
0.08/0.17	 Fresh Variable Processor: loop length: 1
0.08/0.17	                           terms:
0.08/0.17	                            and(tt())
0.08/0.17	                           context: []
0.08/0.17	                           substitution:
0.08/0.17	                            X -> and(tt())
0.08/0.17	  Qed
0.08/0.18	EOF