MAYBE 35.90/10.42 MAYBE 35.90/10.42 35.90/10.42 Problem: 35.90/10.42 a(b(x1)) -> b(b(b(x1))) 35.90/10.42 a(c(x1)) -> c(b(b(x1))) 35.90/10.42 b(a(x1)) -> a(a(a(x1))) 35.90/10.42 b(c(x1)) -> c(c(c(x1))) 35.90/10.42 a(x1) -> x1 35.90/10.42 b(x1) -> x1 35.90/10.42 c(x1) -> x1 35.90/10.42 35.90/10.42 Proof: 35.90/10.42 Open 35.90/10.43 EOF