YES(?,O(n^1))
0.16/0.22	YES(?,O(n^1))
0.16/0.22	
0.16/0.22	Problem:
0.16/0.22	 f(g(f(a()),h(a(),f(a())))) -> f(h(g(f(a()),a()),g(f(a()),f(a()))))
0.16/0.22	
0.16/0.22	Proof:
0.16/0.22	 Bounds Processor:
0.16/0.22	  bound: 1
0.16/0.22	  enrichment: match
0.16/0.22	  automaton:
0.16/0.22	   final states: {4,3,2,1}
0.16/0.22	   transitions:
0.16/0.22	    f1(12) -> 1*
0.16/0.22	    f1(6) -> 10,8,7
0.16/0.22	    h1(11,9) -> 12*
0.16/0.22	    g1(8,7) -> 9*
0.16/0.22	    g1(10,6) -> 11*
0.16/0.22	    a1() -> 6*
0.16/0.22	    f0(2) -> 1*
0.16/0.22	    f0(4) -> 1*
0.16/0.22	    f0(1) -> 1*
0.16/0.22	    f0(3) -> 1*
0.16/0.22	    g0(3,1) -> 2*
0.16/0.22	    g0(3,3) -> 2*
0.16/0.22	    g0(4,2) -> 2*
0.16/0.22	    g0(4,4) -> 2*
0.16/0.22	    g0(1,2) -> 2*
0.16/0.22	    g0(1,4) -> 2*
0.16/0.22	    g0(2,1) -> 2*
0.16/0.22	    g0(2,3) -> 2*
0.16/0.22	    g0(3,2) -> 2*
0.16/0.22	    g0(3,4) -> 2*
0.16/0.22	    g0(4,1) -> 2*
0.16/0.22	    g0(4,3) -> 2*
0.16/0.22	    g0(1,1) -> 2*
0.16/0.22	    g0(1,3) -> 2*
0.16/0.22	    g0(2,2) -> 2*
0.16/0.22	    g0(2,4) -> 2*
0.16/0.22	    a0() -> 3*
0.16/0.22	    h0(3,1) -> 4*
0.16/0.22	    h0(3,3) -> 4*
0.16/0.22	    h0(4,2) -> 4*
0.16/0.22	    h0(4,4) -> 4*
0.16/0.22	    h0(1,2) -> 4*
0.16/0.22	    h0(1,4) -> 4*
0.16/0.22	    h0(2,1) -> 4*
0.16/0.22	    h0(2,3) -> 4*
0.16/0.22	    h0(3,2) -> 4*
0.16/0.22	    h0(3,4) -> 4*
0.16/0.22	    h0(4,1) -> 4*
0.16/0.22	    h0(4,3) -> 4*
0.16/0.22	    h0(1,1) -> 4*
0.16/0.22	    h0(1,3) -> 4*
0.16/0.22	    h0(2,2) -> 4*
0.16/0.22	    h0(2,4) -> 4*
0.16/0.22	  problem:
0.16/0.22	   
0.16/0.22	  Qed
0.16/0.23	EOF