MAYBE 324.44/82.23 MAYBE 324.44/82.23 324.44/82.23 Problem: 324.44/82.23 0(q0(0(x1))) -> 0(0(q0(x1))) 324.44/82.23 0(q0(h(x1))) -> 0(0(q0(h(x1)))) 324.44/82.23 0(q0(1(x1))) -> 0(1(q0(x1))) 324.44/82.23 1(q0(0(x1))) -> 0(0(q1(x1))) 324.44/82.23 1(q0(h(x1))) -> 0(0(q1(h(x1)))) 324.44/82.23 1(q0(1(x1))) -> 0(1(q1(x1))) 324.44/82.23 1(q1(0(x1))) -> 1(0(q1(x1))) 324.44/82.23 1(q1(h(x1))) -> 1(0(q1(h(x1)))) 324.44/82.23 1(q1(1(x1))) -> 1(1(q1(x1))) 324.44/82.23 0(q1(0(x1))) -> 0(0(q2(x1))) 324.44/82.23 0(q1(h(x1))) -> 0(0(q2(h(x1)))) 324.44/82.23 0(q1(1(x1))) -> 0(1(q2(x1))) 324.44/82.23 1(q2(0(x1))) -> 1(0(q2(x1))) 324.44/82.23 1(q2(h(x1))) -> 1(0(q2(h(x1)))) 324.44/82.23 1(q2(1(x1))) -> 1(1(q2(x1))) 324.44/82.23 0(q2(x1)) -> q3(1(x1)) 324.44/82.23 1(q3(x1)) -> q3(1(x1)) 324.44/82.23 0(q3(x1)) -> q4(0(x1)) 324.44/82.23 1(q4(x1)) -> q4(1(x1)) 324.44/82.23 0(q4(0(x1))) -> 1(0(q5(x1))) 324.44/82.23 0(q4(h(x1))) -> 1(0(q5(h(x1)))) 324.44/82.23 0(q4(1(x1))) -> 1(1(q5(x1))) 324.44/82.23 1(q5(0(x1))) -> 0(0(q1(x1))) 324.44/82.23 1(q5(h(x1))) -> 0(0(q1(h(x1)))) 324.44/82.23 1(q5(1(x1))) -> 0(1(q1(x1))) 324.44/82.23 h(q0(x1)) -> h(0(q0(x1))) 324.44/82.23 h(q1(x1)) -> h(0(q1(x1))) 324.44/82.23 h(q2(x1)) -> h(0(q2(x1))) 324.44/82.23 h(q3(x1)) -> h(0(q3(x1))) 324.44/82.23 h(q4(x1)) -> h(0(q4(x1))) 324.44/82.23 h(q5(x1)) -> h(0(q5(x1))) 324.44/82.23 324.44/82.23 Proof: 324.44/82.23 Open 324.44/82.23 EOF