MAYBE 1171.54/296.47 MAYBE 1171.54/296.48 1171.54/296.48 Problem: 1171.54/296.48 0(1(2(x1))) -> 0(2(1(1(x1)))) 1171.54/296.48 0(1(2(x1))) -> 0(2(1(3(x1)))) 1171.54/296.48 0(1(2(x1))) -> 0(2(1(1(3(x1))))) 1171.54/296.48 0(1(2(x1))) -> 0(2(4(1(1(x1))))) 1171.54/296.48 0(1(2(x1))) -> 0(2(4(1(3(x1))))) 1171.54/296.48 0(3(2(x1))) -> 0(2(1(3(x1)))) 1171.54/296.48 0(3(2(x1))) -> 0(2(1(1(3(x1))))) 1171.54/296.48 0(3(2(x1))) -> 0(0(2(1(1(3(x1)))))) 1171.54/296.48 0(1(1(2(x1)))) -> 0(2(1(1(3(x1))))) 1171.54/296.48 0(1(2(2(x1)))) -> 0(2(2(1(1(x1))))) 1171.54/296.48 0(1(2(2(x1)))) -> 0(2(3(2(1(x1))))) 1171.54/296.48 0(1(3(2(x1)))) -> 0(2(1(4(3(x1))))) 1171.54/296.48 0(1(3(2(x1)))) -> 3(3(0(2(1(x1))))) 1171.54/296.48 0(1(3(2(x1)))) -> 3(0(2(4(1(1(x1)))))) 1171.54/296.48 0(1(5(2(x1)))) -> 5(0(2(1(1(x1))))) 1171.54/296.48 0(3(2(2(x1)))) -> 0(0(2(3(2(x1))))) 1171.54/296.48 0(3(2(2(x1)))) -> 0(0(4(2(3(2(x1)))))) 1171.54/296.48 2(0(3(2(x1)))) -> 1(3(0(2(2(x1))))) 1171.54/296.48 3(0(3(2(x1)))) -> 3(0(0(0(2(3(x1)))))) 1171.54/296.48 3(1(5(2(x1)))) -> 0(2(1(5(3(x1))))) 1171.54/296.48 3(3(5(2(x1)))) -> 3(0(2(1(5(3(x1)))))) 1171.54/296.48 4(5(2(2(x1)))) -> 2(5(0(2(4(1(x1)))))) 1171.54/296.48 5(0(1(2(x1)))) -> 0(2(1(3(4(5(x1)))))) 1171.54/296.48 5(0(2(2(x1)))) -> 2(0(2(4(1(5(x1)))))) 1171.54/296.48 5(0(3(2(x1)))) -> 3(0(2(1(4(5(x1)))))) 1171.54/296.48 5(1(2(2(x1)))) -> 0(2(1(5(2(1(x1)))))) 1171.54/296.48 5(1(2(2(x1)))) -> 2(1(5(2(1(1(x1)))))) 1171.54/296.48 0(1(2(4(2(x1))))) -> 4(2(1(0(2(1(x1)))))) 1171.54/296.48 0(1(2(5(2(x1))))) -> 2(0(2(1(5(4(x1)))))) 1171.54/296.48 0(1(5(1(2(x1))))) -> 1(0(2(1(1(5(x1)))))) 1171.54/296.48 0(1(5(5(2(x1))))) -> 0(2(1(5(5(1(x1)))))) 1171.54/296.48 0(5(0(1(2(x1))))) -> 0(4(5(0(2(1(x1)))))) 1171.54/296.48 0(5(0(3(2(x1))))) -> 0(5(0(0(2(3(x1)))))) 1171.54/296.48 0(5(5(2(2(x1))))) -> 0(2(1(5(5(2(x1)))))) 1171.54/296.48 3(0(3(1(2(x1))))) -> 1(3(3(0(2(3(x1)))))) 1171.54/296.48 3(0(3(4(2(x1))))) -> 1(3(4(0(2(3(x1)))))) 1171.54/296.48 4(5(1(4(2(x1))))) -> 2(4(4(4(1(5(x1)))))) 1171.54/296.48 5(0(1(3(2(x1))))) -> 3(5(0(2(1(3(x1)))))) 1171.54/296.48 5(0(3(1(2(x1))))) -> 0(2(1(4(3(5(x1)))))) 1171.54/296.48 5(0(4(2(2(x1))))) -> 2(0(2(4(1(5(x1)))))) 1171.54/296.48 5(1(0(3(2(x1))))) -> 0(4(3(5(1(2(x1)))))) 1171.54/296.48 5(1(0(3(2(x1))))) -> 5(3(1(1(0(2(x1)))))) 1171.54/296.48 5(1(0(5(2(x1))))) -> 3(5(5(0(2(1(x1)))))) 1171.54/296.48 5(1(0(5(2(x1))))) -> 5(0(2(1(5(5(x1)))))) 1171.54/296.48 5(2(0(3(2(x1))))) -> 0(2(5(2(3(1(x1)))))) 1171.54/296.48 1171.54/296.48 Proof: 1171.54/296.48 Open 1171.54/296.48 EOF